
Which of the following products does not match correctly?
A)
B)
C)
D)
Answer
513.6k+ views
Hint: Look at all the options carefully before answering this question as sometimes we neglect the catalyst or many reactants that are placed on a forward arrow but these plays a crucial role in defining a reaction conditions so one must look at all the reaction conditions, reactants and the products given to answer this question.
Complete answer:
We will see all the given reactions and then find which is not correct:
Option A) this option is incorrect as the reaction defines the correct products for this reaction. As this reaction is following Markonikov’s addition which says that hydrogen gets attached to carbon having higher number of hydrogen atoms and this reaction represents this rule correctly.
Option B) This is an incorrect option as this reaction provides correct products.
Option C) this is an incorrect option as this reaction provides correct products. This reaction represents formation of alkene from an alkyl halide in presence of a base and ethanol. The products given are correct.
Option D) this reaction is incorrect as it defines Anti markonikov’s reaction as this reaction is taking place in the presence of hydrogen bromide in the presence of peroxide. Markonikov’s addition says that hydrogen will get attached to the carbon having higher number of hydrogen atoms. But this reaction is following anti markonikov’s rule which is vice versa of markovnikov's rule thus these products in the following reaction do not match correctly. Thus this is a correct option.
Note:
As we know, anti markovnikov's rule is vice versa of markovnikov's rule. Anti markonikov’s addition takes place in presence of hydrogen peroxide whereas there is no hydrogen peroxide in markovnikov's addition. Markonikov’s addition says that hydrogen will get attached to the carbon having higher number of hydrogen atoms.
Complete answer:
We will see all the given reactions and then find which is not correct:
Option A) this option is incorrect as the reaction defines the correct products for this reaction. As this reaction is following Markonikov’s addition which says that hydrogen gets attached to carbon having higher number of hydrogen atoms and this reaction represents this rule correctly.
Option B) This is an incorrect option as this reaction provides correct products.
Option C) this is an incorrect option as this reaction provides correct products. This reaction represents formation of alkene from an alkyl halide in presence of a base and ethanol. The products given are correct.
Option D) this reaction is incorrect as it defines Anti markonikov’s reaction as this reaction is taking place in the presence of hydrogen bromide in the presence of peroxide. Markonikov’s addition says that hydrogen will get attached to the carbon having higher number of hydrogen atoms. But this reaction is following anti markonikov’s rule which is vice versa of markovnikov's rule thus these products in the following reaction do not match correctly. Thus this is a correct option.
Note:
As we know, anti markovnikov's rule is vice versa of markovnikov's rule. Anti markonikov’s addition takes place in presence of hydrogen peroxide whereas there is no hydrogen peroxide in markovnikov's addition. Markonikov’s addition says that hydrogen will get attached to the carbon having higher number of hydrogen atoms.
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