Answer
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Hint: Read the Aufbau’s principle to obtain the answer for this question. You can also take a look at the periodic table to see which group is filled before the 5f orbital.
Complete step by step answer:
-According to Aufbau’s principle, ‘In the ground state of the atoms, the orbitals are filled with electrons in the order of their increasing energies.’
-Orbitals are filled in the order of increasing value of (n+l). For example, for 3d, n=3 and l=2, so, (n+l)=5 and for 4s, n=4 and l=0, so, (n+l)=4. As the value of (n+l) for 4s orbital is less than that of 3d orbital, 4s orbital is filled before 3d orbitals.
-Similarly, let us calculate (n+l) values for all the orbitals given in the question.
For 5f orbital, n=5 and l=3, so (n+l)=8
For 4f orbital, n=4 and l=3, so (n+l)=7
For 7s orbital, n=7 and l=0, so (n+l)=7
For 5d orbital, n=5 and l=2, so (n+l)=7
For 6d orbital, n=6 and l=2, so (n+l)=8
-If two orbitals have the same value of (n+l), then the orbital with lower value of n will be filled first. Now here, 4f has the least n-value so it will be filled first. Then comes, 5d and then 7s orbitals followed by 5f orbital and then 6d orbital.
-Aufbau’s diagram is shown below:
-Therefore, we can conclude that 7s-orbital is filled just before 5f-orbital.
So, the correct answer is “Option B”.
Note: Learn the Aufbau schematic diagram. Remember according to the rules, we need to check (n+l) values first and then if they are the same, then we go for an orbital having lower n-value.
Complete step by step answer:
-According to Aufbau’s principle, ‘In the ground state of the atoms, the orbitals are filled with electrons in the order of their increasing energies.’
-Orbitals are filled in the order of increasing value of (n+l). For example, for 3d, n=3 and l=2, so, (n+l)=5 and for 4s, n=4 and l=0, so, (n+l)=4. As the value of (n+l) for 4s orbital is less than that of 3d orbital, 4s orbital is filled before 3d orbitals.
-Similarly, let us calculate (n+l) values for all the orbitals given in the question.
For 5f orbital, n=5 and l=3, so (n+l)=8
For 4f orbital, n=4 and l=3, so (n+l)=7
For 7s orbital, n=7 and l=0, so (n+l)=7
For 5d orbital, n=5 and l=2, so (n+l)=7
For 6d orbital, n=6 and l=2, so (n+l)=8
-If two orbitals have the same value of (n+l), then the orbital with lower value of n will be filled first. Now here, 4f has the least n-value so it will be filled first. Then comes, 5d and then 7s orbitals followed by 5f orbital and then 6d orbital.
-Aufbau’s diagram is shown below:
-Therefore, we can conclude that 7s-orbital is filled just before 5f-orbital.
So, the correct answer is “Option B”.
Note: Learn the Aufbau schematic diagram. Remember according to the rules, we need to check (n+l) values first and then if they are the same, then we go for an orbital having lower n-value.
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