How do write \[54\] as a product of prime factors?
Answer
Verified
441.9k+ views
Hint: We need to know the first ten prime numbers in the natural numbers. This question describes the operation of multiplication/ division. The final answer should involve only prime numbers. The definition of prime numbers is a number that is divided only by \[1\] and itself, otherwise, it cannot be divided by any numbers.
Complete step by step solution:
In this question, we have to write \[54\] as a product of prime number factors.First, we should know about prime numbers. The prime numbers are only divided by \[1\] and itself.Otherwise, it cannot be divided by any numbers. So, the prime numbers are,
\[2,3,5,7,11,13,....\]
To solve the given question we would divide the \[54\] as follows,
From the given prime numbers we can use \[2\]. So, when \[2\] is multiplied with \[27\] it will be\[54\]. As a next step, we didn’t simplify \[2\]. So, we try to simplify \[27\]. \[27\] can be divided into \[3\] and \[9\]. So, we get
From the above step we cannot simplify \[3\], but we can simplify \[9\]. So, \[9\] can be simplified as \[3 \times 3\]. Here \[3\] is a prime number so we can go to the next step.
So, the final answer is, the product of prime factor for \[54\] is shown below,
\[54 = 2 \times 3 \times 3 \times 3\]
(or)
\[54 = 2 \times {3^3}\]
Note: In this type of question we would use the operation of addition/ subtraction/ multiplication/ division. We need to know the first ten prime numbers. Note that \[1\] is not a prime number and \[1\] is not a non-prime number, it is an exception. All the factors should be a prime number, we don’t use a non-prime number as a factor. Also, we don’t use this \[0\] as a factor in this type of question.
Complete step by step solution:
In this question, we have to write \[54\] as a product of prime number factors.First, we should know about prime numbers. The prime numbers are only divided by \[1\] and itself.Otherwise, it cannot be divided by any numbers. So, the prime numbers are,
\[2,3,5,7,11,13,....\]
To solve the given question we would divide the \[54\] as follows,
From the given prime numbers we can use \[2\]. So, when \[2\] is multiplied with \[27\] it will be\[54\]. As a next step, we didn’t simplify \[2\]. So, we try to simplify \[27\]. \[27\] can be divided into \[3\] and \[9\]. So, we get
From the above step we cannot simplify \[3\], but we can simplify \[9\]. So, \[9\] can be simplified as \[3 \times 3\]. Here \[3\] is a prime number so we can go to the next step.
So, the final answer is, the product of prime factor for \[54\] is shown below,
\[54 = 2 \times 3 \times 3 \times 3\]
(or)
\[54 = 2 \times {3^3}\]
Note: In this type of question we would use the operation of addition/ subtraction/ multiplication/ division. We need to know the first ten prime numbers. Note that \[1\] is not a prime number and \[1\] is not a non-prime number, it is an exception. All the factors should be a prime number, we don’t use a non-prime number as a factor. Also, we don’t use this \[0\] as a factor in this type of question.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
10 examples of friction in our daily life
The correct order of melting point of 14th group elements class 11 chemistry CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
State and prove Bernoullis theorem class 11 physics CBSE
What organs are located on the left side of your body class 11 biology CBSE