Question

Write all the factors of the number 27.

Answer 1

Hint: To solve this question we have to check all the numbers that are completely divisible by the number 27. If they are completely divisible then they are the factors otherwise they are not. Then we take common terms from those factors and they are the factors.

Complete step-by-step solution:
To find,
All the factors of a number 27
So first we divide 27 by 1 then we didn’t get any reminder so 1 is a factor and can be written as
\[27 = 1 \times 27\]
From here both are the factors
Now we check 2 then we find some reminders because 27 is added and 2 is even.
From here all even numbers are rejected (4,6,8,10,12…………….)
Now we check 3 here also we will not find any reminder and can be written as.
\[27 = 3 \times 9\]
From here 3 and 9 both are the factors
Now we check with 5 and find that 5 gives the reminder.
So all numbers that are divisible by 5 are rejected (5,10,15…….)
7 is not a factor because 7 is a prime number.
 From here prime numbers are rejected.
And after 13 we found that the number is less than 1 so that is not completely divisible
From here we found that the factors of the number are 1, 3, 9, 27
Final answer:
\[27 = 1 \times 27\]
\[27 = 3 \times 9\]
\[27 = 9 \times 3\]
\[27 = 27 \times 1\]
So the factors are 1, 27, 3, 9.

Note: We can solve this question by another method that is by finding the HCF of the following number and after that making pairs of all those numbers to find different-different results. Two factors are always possible for each and every number. That is 1 and that number as well.