Answer
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Hint:We know that in organic chemistry, the chemical formula provides us a way to represent any chemical substance using the symbol of the elements present in it. The molecular formula for the compound acetate is \[C{H^3}CO{O^ - }\] and ‘Pb’ is lead.
Complete answer:
\[C{H^3}CO{O^ - }\] is the acetate ion which means it has a negative charge of \[\; - 1\]. This ion is very common, for instance vinegar is, for the most part, acetic acid CH3COOH. This means that the negative charge of -1 has been filled with a hydrogen proton, charge of \[ + 1\].
And Pb stands for the element ‘Lead’. Since. there are two oxidation state of Pb i.e. \[ + 2\] and \[ + 4\] then the only way for the total charge of the compound to be zero is:
\[ \Rightarrow Pb\left( { + 2} \right) + 2acetate\left( { - 1} \right) = 2 + \left( { - 2} \right) = 0\]
Hence, the oxidation state of the lead is \[ + 2\] here.
So, the name of the compound \[{(C{H_3}COO)_2}Pb\] is known as lead (II) acetate or commonly known as lead acetate and it is a type of sweet, white powder that is crystal-like. It is also soluble in both water and glycerine.
Therefore, the chemical name of the compound \[{(C{H_3}COO)_2}Pb\] is Lead(II) acetate.
Note:
It should be noted that the other name of Lead(II) acetate (\[Pb{\left( {C{H_3}COO} \right)_2}\]), are also lead acetate, lead diacetate, plumbous acetate, sugar of lead, lead sugar, salt of Saturn, lead salt, or Goulard's powder. Lead(II) acetate is used as a reagent to make other lead compounds and also as a fixative for some dyes. In low concentrations, it is the principal active ingredient in progressive types of hair colouring dyes.
Complete answer:
\[C{H^3}CO{O^ - }\] is the acetate ion which means it has a negative charge of \[\; - 1\]. This ion is very common, for instance vinegar is, for the most part, acetic acid CH3COOH. This means that the negative charge of -1 has been filled with a hydrogen proton, charge of \[ + 1\].
And Pb stands for the element ‘Lead’. Since. there are two oxidation state of Pb i.e. \[ + 2\] and \[ + 4\] then the only way for the total charge of the compound to be zero is:
\[ \Rightarrow Pb\left( { + 2} \right) + 2acetate\left( { - 1} \right) = 2 + \left( { - 2} \right) = 0\]
Hence, the oxidation state of the lead is \[ + 2\] here.
So, the name of the compound \[{(C{H_3}COO)_2}Pb\] is known as lead (II) acetate or commonly known as lead acetate and it is a type of sweet, white powder that is crystal-like. It is also soluble in both water and glycerine.
Therefore, the chemical name of the compound \[{(C{H_3}COO)_2}Pb\] is Lead(II) acetate.
Note:
It should be noted that the other name of Lead(II) acetate (\[Pb{\left( {C{H_3}COO} \right)_2}\]), are also lead acetate, lead diacetate, plumbous acetate, sugar of lead, lead sugar, salt of Saturn, lead salt, or Goulard's powder. Lead(II) acetate is used as a reagent to make other lead compounds and also as a fixative for some dyes. In low concentrations, it is the principal active ingredient in progressive types of hair colouring dyes.
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