Question

Write the following in Roman numerals $248$

Answer 1

Hint:Let the given number is $248$.We need to find out $248$ in Roman numerals.First we write standard roman numerals $$1=I,2=II,3=III,5=V,10=X,50=L,100=C,500=C,1000=M$$
Using the above and following some patterns we will get the result.

Complete step-by-step answer:
It is given that the number is $$248$$
We have to find Roman numeral of $$248$$.
We have some facts about numbers into roman numerals.
$1=I$, $5=V$, $10=X$, $50=L$, $100=C$
After these facts we can write the some more roman numerals by helping some rules of one
$1=I$, $2=II$, $3=III$ in the same pattern
But for $4$ we cannot write like this because we have a standard symbol for $5$ which is equal to $$V$$ because $4$ is immediately left on the number line so we write one number less than $5$.
Hence we can write $4$ as follows:
$4=5-1$
So we can write,
$4=IV$
Also we know,
$$5=V$$,
Rule $1$: We have some facts when we have standard symbols for the roman numerals and we need to write an increased number so we added symbols on the right side of the given number or vice versa.
For example:
$6=VI$, $7=VII$, $8=VIII$,
Again following the same rule concept done by the number $$4$$ and $$5$$
Here we can get, $9=IX$, $10=X$….
We follow likewise pattern by the rule$1$
$11=XI$, $12=XII$, $15=XV$…….
Now, followed the same concept for $248$
We need to find out the Roman numeral for $248$
First we write largest Roman numeral to approach $248$, so we can write by applying rules and standard terminologies (mention above),
We split the number $248=100+100+\left(50-10\right)+5+3$
Now converting each in roman numerals $248=C+C+XL+V+III$
Hence $248=CCXLVIII$

Note:A smaller digit is to be added when it is placed just following the larger digit and is to be subtracted when it is placed on the left of the larger digit.