Answer
396.9k+ views
Hint: To solve this question we have to know briefly about gravitational force. Newton's Law of Universal Gravitation is utilized to clarify gravitational power. This law expresses that each monstrous molecule in the universe pulls in each other gigantic molecule with a power which is straightforwardly corresponding to the result of their masses and contrarily relative to the square of the distance between them. This general, actual law was gotten from perceptions made by enlistment.
Complete step by step answer:
Another way, more current, approach to express the law is: 'each point mass draws in each and every other point mass by a power pointing along the line crossing the two focuses. The power is corresponding to the result of the two masses and conversely relative to the square of the distance between the point masses'.
We know that, The gravitational force between the earth and an object on the surface of the earth is \[F = G\dfrac{{Mm}}{{{d^2}}}\]
Where we know that, $G$ is the universal gravitational constant. And here $M$ is the mass of earth. $m$ is known to the mass of an object on the surface of earth and we can assume now that $d$ is the distance between two bodies.
Note: We have to know that, The gravitational field is the negative differential of the gravitational potential. Presently the gravitational potential because of a molecule a ways off $r$ is $ −G\dfrac{m}{r}$ where $m$ is the mass of the molecule.
Complete step by step answer:
Another way, more current, approach to express the law is: 'each point mass draws in each and every other point mass by a power pointing along the line crossing the two focuses. The power is corresponding to the result of the two masses and conversely relative to the square of the distance between the point masses'.
We know that, The gravitational force between the earth and an object on the surface of the earth is \[F = G\dfrac{{Mm}}{{{d^2}}}\]
Where we know that, $G$ is the universal gravitational constant. And here $M$ is the mass of earth. $m$ is known to the mass of an object on the surface of earth and we can assume now that $d$ is the distance between two bodies.
Note: We have to know that, The gravitational field is the negative differential of the gravitational potential. Presently the gravitational potential because of a molecule a ways off $r$ is $ −G\dfrac{m}{r}$ where $m$ is the mass of the molecule.
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