Answer
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Hint – In this question use the basic relationship between the charge, potential and capacitance that is C = (Q/V), then use the basic S.I. units of charge and potential. Substitute them into the relationship to get the required S.I. unit of capacitance. This will help approach the solution.
Step-By-Step answer:
Capacitance
Capacitance of a material is the ability of a material to store charges in it.
It is also known as the ratio of the change in the electric charge to the change in the electric potential.
It is often denoted by C.
Therefore, C = (Q/V), where, Q = charge, and V = potential.
As we know that the S.I unit of charge (Q) is Coulomb and the S.I unit of potential is volts.
So capacitance is the ability to store 1 Coulomb of charge per potential.
So the unit of capacitance is Coulomb per volts.
Therefore, the unit of capacitance = Coulomb/volts.
But it is not the S.I unit of the capacitance, S.I unit of the capacitance is Farad, often denoted by (F).
It is named after the English Physicist Michael Faraday.
Other units are micro farad $\left( {\mu F} \right)$, nanofarad $\left( {nF} \right)$, picofarad $\left( {pF} \right)$ etc.
The dimension of the capacitance is $\left[ {{M^{ - 1}}{L^{ - 2}}{T^4}{A^2}} \right]$.
Where, M is the dimension of the mass, L is the dimension of the length, T is the dimension of the second and A is the dimension of the current.
So the S.I unit of the capacitance is Farad (F).
So this is the required answer.
Note – SI units is known as international systems of units, it is a system of physical units based upon the meter, kilogram, second, ampere, kelvin, candela and mole together with a set of prefixes to indicate the multiplication or division by a power of 10.
Step-By-Step answer:
Capacitance
Capacitance of a material is the ability of a material to store charges in it.
It is also known as the ratio of the change in the electric charge to the change in the electric potential.
It is often denoted by C.
Therefore, C = (Q/V), where, Q = charge, and V = potential.
As we know that the S.I unit of charge (Q) is Coulomb and the S.I unit of potential is volts.
So capacitance is the ability to store 1 Coulomb of charge per potential.
So the unit of capacitance is Coulomb per volts.
Therefore, the unit of capacitance = Coulomb/volts.
But it is not the S.I unit of the capacitance, S.I unit of the capacitance is Farad, often denoted by (F).
It is named after the English Physicist Michael Faraday.
Other units are micro farad $\left( {\mu F} \right)$, nanofarad $\left( {nF} \right)$, picofarad $\left( {pF} \right)$ etc.
The dimension of the capacitance is $\left[ {{M^{ - 1}}{L^{ - 2}}{T^4}{A^2}} \right]$.
Where, M is the dimension of the mass, L is the dimension of the length, T is the dimension of the second and A is the dimension of the current.
So the S.I unit of the capacitance is Farad (F).
So this is the required answer.
Note – SI units is known as international systems of units, it is a system of physical units based upon the meter, kilogram, second, ampere, kelvin, candela and mole together with a set of prefixes to indicate the multiplication or division by a power of 10.
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