","comment":{"@type":"Comment","text":" Solve using inverse variation."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" Direct variation ","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" Undefined ","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" None of the above","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" Inverse variation","position":0,"answerExplanation":{"@type":"Comment","text":" Given table shows how books are divided equally with respect to students. $$ \\\\ $$ Hence, considering both number of students with respect to books we have: $$ \\\\ 2\\left( {12} \\right) = 24$$ ,$$4\\left( 6 \\right) = 24$$, $$3\\left( 8 \\right) = 24$$, $$8\\left( 3 \\right) = 24$$ and $$6\\left( 4 \\right) = 24 \\\\ $$ We get, $$ \\Rightarrow xy = 24$$ $$ \\\\ $$ I.e., the product is always the same for both numbers of students with respect to books. Therefore, the relationship is inversely variation i.e., $$ y = \\dfrac{{24}}{x}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Direct and inverse variation Quiz 1","text":" Find $$y$$ when $$x = 5$$, If $$y$$ varies inversely with $$x$$ and $$y = 10$$ when $$x = 2$$.","comment":{"@type":"Comment","text":" Use the equation ${x_1}{y_1} = {x_2}{y_2}$, when two variables are given to solve this question."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$1$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$5$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$0$$","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$4$$","position":3,"answerExplanation":{"@type":"Comment","text":" Here we have given, with the values of $$x$$ and $$y$$ as: $$ \\\\ {x_1}{y_1} = {x_2}{y_2} \\\\ \\Rightarrow 2\\left( {10} \\right) = 5y \\\\ $$ Evaluating the terms, we get: $$ \\\\ \\Rightarrow 20 = 5y \\\\ \\Rightarrow y = \\dfrac{{20}}{5} \\\\ \\Rightarrow y = 4$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Direct and inverse variation Quiz 1","text":" Find the length of the paper that was $$30cm$$ before it was reduced in the ratio $$5:2$$.","comment":{"@type":"Comment","text":" Use the concept of direct variation to solve this question as the length is varied."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$23cm$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$10cm$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$1cm$$","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$12cm$$","position":3,"answerExplanation":{"@type":"Comment","text":" Given, Length of paper is $$30cm$$. $$ \\\\ $$ Now, let the original length be $$5x$$ and the reduced length of paper be $$2x$$. $$ \\\\ $$ But, $$5x = 30$$; hence we get: $$ \\\\ x = \\dfrac{{30}}{5} \\\\ \\Rightarrow x = 6 \\\\ $$ Therefore, we know that the reduced length is $$2cm$$ i.e., $$2x$$ $$ \\\\ \\Rightarrow 2\\left( 6 \\right) = 12cm$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}