","comment":{"@type":"Comment","text":" The density of the body is less than that of liquid so the body will be pushed upward due to large buoyant force acting on it. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"$$15m/{{s}^{2}}$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":"$$5m/{{s}^{2}}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":"$$20m/{{s}^{2}}$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$10m/{{s}^{2}}$$","position":0,"answerExplanation":{"@type":"Comment","text":" $$\\\\ $$ Weight of body $$ = mg =50\\times 10=500N$$ $$ \\\\ $$ So, the total downward force will be 500N. $$ \\\\ $$ Volume of body, $$V=\\dfrac{\\text{mass}}{\\text{density}} \\\\ \\Rightarrow V =\\dfrac{50}{500}\\\\ \\Rightarrow V =0.1{{m}^{3}} \\\\ $$ Buoyant force acting on body $${{F}_{A}}= {{\\rho }_{l}}Vg \\\\ \\Rightarrow {{F}_{A}}=1000\\times 0.1\\times 10\\\\ \\Rightarrow {{F}_{A}}=1000N\\\\ $$ Net force will be in upward direction with a magnitude of $$ 1000N-500N=500N$$ $$ \\\\ $$ Now, mass of object $$ = 50Kg$$ $$ \\\\ $$ $$\\text{Acceleration }= \\dfrac{\\text{Force}}{\\text{mass}} \\\\ \\Rightarrow\\text{Acceleration} =\\dfrac{500}{50}\\\\ \\therefore\\text{Acceleration}=10m/{{s}^{2}}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}