","comment":{"@type":"Comment","text":"First calculate the volume of the water collected. Then find the density of the rainwater, using which you can arrive at the average hydrostatic pressure exerted by it. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$555\\,Nm^{-2}$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$777\\,Nm^{-2}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$888\\,Nm^{-2}$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$666\\,Nm^{-2}$$","position":1,"answerExplanation":{"@type":"Comment","text":" $$\\text{We are given that}\\,10\\,mm = 0.01\\,m\\,\\text{of rainfall is collected over a rooftop of area}\\,A= 250\\,m^2.\\\\ \\text{This means that every square metre of the rooftop receives}\\,0.01\\,m^{3}\\,\\text{of rainfall.}\\\\ \\text{Therefore,}\\,250m^{2}\\,\\text{of rooftop receives a volume of:}\\\\ V = 0.01 \\times 250\\\\ \\Rightarrow V = 2.5\\,m^{3}\\,\\text{of rainwater}\\\\ \\text{The mass of the empty tank is 130 kg}\\\\ \\text{and the mass of the tank filled with water is 300 kg.}\\\\ \\text{Therefore, the mass of the rainwater collected will be:}\\\\ m = 300-130 = 170\\,kg\\\\ \\text{The density of the collected rainwater will be:}\\\\ \\rho = \\dfrac{m}{V}\\\\ \\Rightarrow\\rho = \\dfrac{170}{2.5}\\\\ \\Rightarrow\\rho = 68\\,kgm^{-3}\\\\ \\text{The average pressure exerted by the rainwater on the walls of the tank will be equivalent to}\\\\ \\text{the hydrostatic pressure at half the height of the fully filled tank at 1 m,i.e.}\\\\ P = \\rho g h\\\\ \\Rightarrow P = 68 \\times 9.8 \\times 1\\\\ \\therefore P= 666.4 \\approx 666\\,Nm^{-2}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}