","comment":{"@type":"Comment","text":" First find the energy imparted from the heating element to the solid and then arrive at its specific heat. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{It}{Vm\\Delta T}$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{Vt}{\\Delta T}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{IV}{m\\Delta T}$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{IVt}{m\\Delta T}$$","position":1,"answerExplanation":{"@type":"Comment","text":" $$\\text{The power of an ohmic circuit can be given as:}\\\\ P = I \\times V\\\\ \\text{The energy supplied by the DC power supply to}\\\\ \\text{the heating element is the product of its power and time, i.e.,}\\\\ E = P \\times t = IVt\\\\ \\text{This energy is the one that is imparted to the solid}\\\\ \\text{where it gets heated through a temperature of}\\,\\Delta T\\, i.e.,\\\\ E = \\Delta Q\\\\ \\text{If s is the specific heat of the solid, then}\\\\ \\Rightarrow IVt = m s\\Delta T\\\\ \\therefore s = \\dfrac{IVt}{m\\Delta T}$$ ","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Specific heat capacity Quiz 1","text":"Automotive cooling systems work by passing a liquid coolant through the pipes and passages surrounding the engine block. As the coolant flows through these passages it picks up heat from the engine and makes its way through a hose to the radiator at the front end of a car where the stream of air entering the engine compartment via the grills of the car cools the heated coolant.$$\\\\$$ Having understood how this system works you decide to probe into the thermodynamics of the coolant in your car. You find that there is $$5\\,litres $$ of coolant, which is an equal-parts mixture of water and antifreeze $$(\\text{ethylene glycol})$$. It absorbs a heat of $$73.5 \\times 10^3\\,J$$, lowering the temperature of the engine compartment from $$105^{\\circ}C$$ to $$88^{\\circ}C$$ while maintaining a constant pressure. Determine the specific heat capacity of the coolant, if it has a density of $$1055\\,kgm^{-3}$$. ","comment":{"@type":"Comment","text":"Find the mass of the coolant following which you can plug it into a suitable expression to find its specific heat capacity. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$0.41\\,Jg^{-1}K^{-1}$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$410\\,Jg^{-1}K^{-1}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$820\\,Jg^{-1}K^{-1}$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$0.82\\,Jg^{-1}K^{-1}$$","position":0,"answerExplanation":{"@type":"Comment","text":"$$\\text{Given that, for the coolant,}\\\\ \\text{Density}\\,\\rho = 1055 \\,kgm^{-3}\\,\\text{and Volume}\\, V = 5\\,litres = 5 \\times 10^{-3}\\,m^3.\\\\ \\text{The mass of the coolant will be:}\\\\ m = \\rho \\times V\\\\ \\Rightarrow m = 1055 \\times 5 \\times 10^{-3}\\\\ \\Rightarrow m = 5.275\\,kg\\\\ \\Rightarrow m = 5275\\,g\\\\ \\text{Now, the coolant absorbs a heat of}\\,\\Delta Q = 73.5 \\times 10^{3}\\,J\\,\\text{such that,}\\\\ \\Delta T = (105-88)^{\\circ}C \\equiv 17\\,K\\\\ \\text{Therefore, the specific heat of the coolant will be:}\\\\ s = \\dfrac{\\Delta Q}{m\\Delta T}\\\\ \\Rightarrow s = \\dfrac{73.5 \\times 10^{3}}{5275 \\times 17}\\\\ \\therefore s = 0.82\\,Jg^{-1}K^{-1}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}