$$ \\\\ $$ The power of conducting electricity $$($$Strength of the conductor$$)$$ will follow the trend as,","comment":{"@type":"Comment","text":" Calculate resistance of all, the conductor with least resistance will be highly conducting electricity as conductance is the reciprocal of resistance. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$X > Z > Y$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$Z > Y > X$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$Y > X > Z$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$X = Y = Z$$","position":0,"answerExplanation":{"@type":"Comment","text":" The resistance of first metallic slab X will be, $$ \\\\R=\\dfrac{\\rho \\times 10}{100}\\\\\\Rightarrow R=\\dfrac{\\rho }{10}\\text{ }\\Omega\\\\$$ The resistance of metallic slab Y will be, $$ \\\\ R=\\dfrac{\\rho \\times 20}{200}\\\\\\Rightarrow R=\\dfrac{\\rho }{10}\\text{ }\\Omega\\\\ $$ The resistance of metallic slab Z will be, $$ \\\\ R=\\dfrac{\\rho \\times 30}{300}\\\\\\therefore R=\\dfrac{\\rho }{10}\\text{ }\\Omega\\\\ $$ Here, all the resistances are equal in nature. Hence the conductivity will also be equal in nature.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Electric insulators and conductors Quiz 1","text":"Suman was holding a spherical conductor of radius $$r$$ and whose potential is measured to be an approximate value of $$120V$$ . Tanuja snatched the conductor from Suman and placed it inside another spherical conductor which is hollow and its diameter is $$12m$$ . She placed the conductor inside the shell such that the conductor just touches the shell. If the potential of the hollow shell is $$40V$$ , then what is the value of radius $$r$$ of the conductor? ","comment":{"@type":"Comment","text":"The electric potential will be the ratio of the product of the dielectric constant and the charge in it to the radius of the conducting material."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$1m$$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$3m$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$4m$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$2m$$","position":1,"answerExplanation":{"@type":"Comment","text":" The potential can be written as,$$ \\\\V=\\dfrac{Kq}{r}\\\\ $$ Substituting the values in the equation will give, $$ \\\\40=\\dfrac{Kq}{6} \\\\\\Rightarrow Kq=6\\times 40 \\\\ $$ The another potential can be written as, $$ \\\\ 120=\\dfrac{Kq}{r}\\\\ $$ Substituting the values in it, $$ \\\\ 120=\\dfrac{6\\times 40}{r} \\\\\\therefore r=2\\text{ }m$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}