","comment":{"@type":"Comment","text":"Right hand thumb rule is used to measure the direction of net magnetic field in the loop and the direction of magnetic field and induced current is measured. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" Clockwise and outwards","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" Anti-clockwise and outwards","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" Anti-clockwise and into the plane","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" Clockwise and into the plane","position":2,"answerExplanation":{"@type":"Comment","text":" The magnetic field due to left wire is directed into the plane of the square loop perpendicularly and its magnetic flux is decreasing and due to right wire magnetic field is in outward direction in the loop and magnetic flux is decreasing. The left wire is closer to the loop than the right wire so the change in magnetic flux will be greater from the left wire which will be considered for the direction of current. $$ \\\\ $$ The decrease in flux in the loop is opposed by the current induced in the loop by producing a magnetic field in the same direction as the magnetic field of the wire. Again from right hand rule, for this inward magnetic field, the direction of the induced current in the loop is clockwise.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Electromagnetic induction Quiz 1","text":" The rod of length 1 m in a given circuit is moving with a constant velocity of 12m/s towards right in a magnetic field of 2 T into the plane. Find the induced current in a circuit. $$ \\\\ $$ ","comment":{"@type":"Comment","text":"The formula for induced emf in a moving rod is used to calculate voltage in a circuit and equivalent resistance is calculated after which current flowing in a circuit can be calculated. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 10 A","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" 8 A","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" 14 A","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 12 A","position":0,"answerExplanation":{"@type":"Comment","text":" Induced emf in a moving rod is given by, $$ \\\\ \\Rightarrow E=BLV \\\\ \\Rightarrow E=2\\times 1\\times 12=24V \\\\ $$ Net resistance in the circuit, $$ \\\\ \\Rightarrow\\dfrac{1}{R}=\\dfrac{1}{{{R}_{1}}}+\\dfrac{1}{{{R}_{2}}}\\\\ \\Rightarrow\\dfrac{1}{R}=\\dfrac{1}{4}+\\dfrac{1}{4}\\\\ \\Rightarrow\\dfrac{1}{R}=\\dfrac{1}{2} \\\\ \\Rightarrow R=2\\Omega \\\\ \\Rightarrow I=\\dfrac{E}{R}\\\\ \\Rightarrow R=\\dfrac{24}{2}\\\\ \\therefore R=12A$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Electromagnetic induction Quiz 1","text":" A loop of wire having radius 8 cm is placed in a varying magnetic field region with time. The change in magnetic field with time is shown in figure. Calculate the emf induced between 0-3 sec. $$ \\\\ $$
","comment":{"@type":"Comment","text":"The change in magnetic field is responsible for change in flux by which lenz’s law can be applied and emf induced is calculated"},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$7\\times {{10}^{-3}}V$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$4.5\\times {{10}^{-3}}V$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$3.5\\times {{10}^{-3}}V$$","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$5.35\\times {{10}^{-3}}V$$","position":3,"answerExplanation":{"@type":"Comment","text":" By lenz's law and change in flux we have $$ \\\\ \\Rightarrow \\phi =BA \\\\ \\Rightarrow \\dfrac{d\\phi }{dt}=\\dfrac{dB}{dt}A \\\\ \\Rightarrow E=\\dfrac{dB}{dt}A=\\dfrac{dB}{dt}\\times \\pi {{r}^{2}} \\\\ \\Rightarrow E = \\dfrac{dB}{dt}A\\\\ \\Rightarrow E=\\dfrac{0.8}{3}\\times \\pi \\times {{8}^{2}}\\times {{10}^{-2}} \\\\ \\Rightarrow E=5.35\\times {{10}^{-3}}V $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}