Answer
Verified
89.4k+ views
Hint: Generally, the temperature has three units, they are Kelvin, Celsius and Fahrenheit. And these three units have the relation between them. One unit is changed to another unit by using that relationship. In this problem, it is given that, the temperature in Fahrenheit scale and asking the temperature in Celsius scale, so by using the relation between the Fahrenheit and Celsius the solution can be determined.
Useful formula:
The conversion of the temperature scale from Fahrenheit to the Celsius is,
$C = \dfrac{5}{9}\left( {F - 32} \right)$
Where, $C$ is the temperature in Celsius and $F$ is the temperature in Fahrenheit
Complete step by step solution:
Given that,
The temperature in Fahrenheit, $T = {200^ \circ }\,F$
The conversion of the temperature scale from Fahrenheit to the Celsius is,
$C = \dfrac{5}{9}\left( {F - 32} \right)\,.................\left( 1 \right)$
By substituting the temperature in Fahrenheit in the above equation (1), then the equation (1) is written as,
$C = \dfrac{5}{9}\left( {200 - 32} \right)$
On subtracting the terms inside the bracket, then the above equation is written as,
$C = \dfrac{5}{9}\left( {168} \right)$
Now multiplying the terms, then the above equation is written as,
$C = \dfrac{{840}}{9}$
On dividing the above equation, then the above equation is written as,
$C = {93.3^ \circ }\,C$
Thus, the above equation shows the temperature in the Celsius scale.
Hence, the option (C) is the correct answer.
Note: The Celsius scale and the Fahrenheit scale will coincide at the temperature of $ - {40^ \circ }$, at this point both Celsius and the Fahrenheit are the same. But the conversion of Celsius to Kelvin is the simple form, zero degree Celsius is equal to the $273.15$ Kelvin.
Useful formula:
The conversion of the temperature scale from Fahrenheit to the Celsius is,
$C = \dfrac{5}{9}\left( {F - 32} \right)$
Where, $C$ is the temperature in Celsius and $F$ is the temperature in Fahrenheit
Complete step by step solution:
Given that,
The temperature in Fahrenheit, $T = {200^ \circ }\,F$
The conversion of the temperature scale from Fahrenheit to the Celsius is,
$C = \dfrac{5}{9}\left( {F - 32} \right)\,.................\left( 1 \right)$
By substituting the temperature in Fahrenheit in the above equation (1), then the equation (1) is written as,
$C = \dfrac{5}{9}\left( {200 - 32} \right)$
On subtracting the terms inside the bracket, then the above equation is written as,
$C = \dfrac{5}{9}\left( {168} \right)$
Now multiplying the terms, then the above equation is written as,
$C = \dfrac{{840}}{9}$
On dividing the above equation, then the above equation is written as,
$C = {93.3^ \circ }\,C$
Thus, the above equation shows the temperature in the Celsius scale.
Hence, the option (C) is the correct answer.
Note: The Celsius scale and the Fahrenheit scale will coincide at the temperature of $ - {40^ \circ }$, at this point both Celsius and the Fahrenheit are the same. But the conversion of Celsius to Kelvin is the simple form, zero degree Celsius is equal to the $273.15$ Kelvin.
Recently Updated Pages
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main
What does a hydrometer consist of A A cylindrical stem class 9 physics JEE_Main
A motorcyclist of mass m is to negotiate a curve of class 9 physics JEE_Main
Other Pages
The diagram given shows how the net interaction force class 11 physics JEE_Main
Ethylidene dichloride is obtained by the reaction of class 12 chemistry JEE_Main
Assertion The trajectory of a projectile is quadratic class 11 physics JEE_Main
Which of the following meet the requirements of Huckel class 11 chemistry JEE_Main
A block of mass 5 kg is on a rough horizontal surface class 11 physics JEE_Main
Choose the incorrect statement from the following A class 12 physics JEE_Main