
A metallic block has no potential difference applied across it, then the mean velocity of free electrons at absolute temperature T is
A. Proportional to T
B. Proportional to \[\sqrt T \]
C. Zero
D. Finite but independent of T
Answer
218.7k+ views
Hint: The concept used in this problem is the kinetic theory of gases and the Maxwell-Boltzmann distribution. We will use the Maxwell-Boltzmann distribution to find the mean velocity of free electrons in a metallic block at a given temperature.
Complete step by step solution:
We know that in a metallic block, the conduction of electricity is mainly due to the movement of free electrons. According to the kinetic theory of gases, the velocity distribution of free electrons in a metallic block follows the Maxwell-Boltzmann distribution. The Maxwell-Boltzmann distribution states that the probability of finding an electron with a velocity v is given by
$P(v) = \left(\dfrac{m}{2\pi kT}\right)^{3/2} v^2 e^{-\dfrac{mv^2}{2kT}}$
Now, using this distribution, we can find the mean velocity of free electrons as,
$\bar{v} = \sqrt{\dfrac{8kT}{\pi m}}$
Hence, we can see that the mean velocity of free electrons is directly proportional to $\sqrt T$.
Therefore, the correct option is B.
Note: The Maxwell-Boltzmann distribution describes the velocity distribution of particles in a gas. It is a statistical law that describes the probability of finding a particle with a certain velocity at a given temperature. A Point should be noted that, When all parameters are held equal, the greater the potential difference in the system, the greater the velocity of electrons flowing in a given material will be. The scalar quantity, in the situation of irrotational flow, whose negative gradient matches the velocity is the velocity potential.
Complete step by step solution:
We know that in a metallic block, the conduction of electricity is mainly due to the movement of free electrons. According to the kinetic theory of gases, the velocity distribution of free electrons in a metallic block follows the Maxwell-Boltzmann distribution. The Maxwell-Boltzmann distribution states that the probability of finding an electron with a velocity v is given by
$P(v) = \left(\dfrac{m}{2\pi kT}\right)^{3/2} v^2 e^{-\dfrac{mv^2}{2kT}}$
Now, using this distribution, we can find the mean velocity of free electrons as,
$\bar{v} = \sqrt{\dfrac{8kT}{\pi m}}$
Hence, we can see that the mean velocity of free electrons is directly proportional to $\sqrt T$.
Therefore, the correct option is B.
Note: The Maxwell-Boltzmann distribution describes the velocity distribution of particles in a gas. It is a statistical law that describes the probability of finding a particle with a certain velocity at a given temperature. A Point should be noted that, When all parameters are held equal, the greater the potential difference in the system, the greater the velocity of electrons flowing in a given material will be. The scalar quantity, in the situation of irrotational flow, whose negative gradient matches the velocity is the velocity potential.
Recently Updated Pages
Two discs which are rotating about their respective class 11 physics JEE_Main

A ladder rests against a frictionless vertical wall class 11 physics JEE_Main

Two simple pendulums of lengths 1 m and 16 m respectively class 11 physics JEE_Main

The slopes of isothermal and adiabatic curves are related class 11 physics JEE_Main

A trolly falling freely on an inclined plane as shown class 11 physics JEE_Main

The masses M1 and M2M2 M1 are released from rest Using class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

