
A necklace weighing 50g in air, but it weighs 46g in water. Assume copper is mixed with gold to prepare the necklace. How much copper is present in it? (Specific gravity of gold is 20 and that of copper is 10)
A) m = 25g
B) m = 30g
C) m = 35g
D) m = 20g
Answer
232.8k+ views
Hint: Mass is defined as the measure of the amount of the matter in a body. Weight is defined as the measure of the force of gravity acting on the object. Specific gravity is defined as the ratio of the density of a substance to the density of a given material.
Complete step by step solution:
Given data:
Weight of the necklace in air = 50 g
Weight of the necklace in water = 46 g
The specific gravity of gold = 20
The specific gravity of copper = 10
Let m be the mass of the copper in the necklace.
Then the mass of the gold in the necklace is (50-m).
Let $V_1$ be the volume of copper and $V_2$ be the volume of gold respectively.
Thus the volume of copper, \[{V_1} = \dfrac{m}{{10}}\]
The volume of gold, \[{V_2} = \dfrac{{50 - m}}{{20}}\]
When immersed in water, $\rho = 1g/c{m^3}$
We know that decrease in weight = upthrust
\[ \Rightarrow \left( {50 - 46} \right)g = \left( {{V_1} + {V_2}} \right)\rho g\]
\[ \Rightarrow 4 = \dfrac{m}{{10}} + \dfrac{{50 - m}}{{20}}\]
\[\Rightarrow 80 = 2m + 50 - m\]
\[ \Rightarrow m = 30kg\]
Thus the mass of the copper in the necklace \[ = 30kg\].
Hence the correct option is B.
Note: 1. Specific gravity is also called relative density. The specific gravity of liquids is usually measured by a hydrometer. Specific gravity is a dimensionless quantity as it is a ratio. Relative density is also used to quantify the buoyancy of a substance either in a fluid or in a gas.
2. In weight, changes occur only when mass and gravity changes. Whereas the density changes whenever the pressure and temperature of the object changes.
3. Volume is defined as the amount of space that is occupied by the object.
Complete step by step solution:
Given data:
Weight of the necklace in air = 50 g
Weight of the necklace in water = 46 g
The specific gravity of gold = 20
The specific gravity of copper = 10
Let m be the mass of the copper in the necklace.
Then the mass of the gold in the necklace is (50-m).
Let $V_1$ be the volume of copper and $V_2$ be the volume of gold respectively.
Thus the volume of copper, \[{V_1} = \dfrac{m}{{10}}\]
The volume of gold, \[{V_2} = \dfrac{{50 - m}}{{20}}\]
When immersed in water, $\rho = 1g/c{m^3}$
We know that decrease in weight = upthrust
\[ \Rightarrow \left( {50 - 46} \right)g = \left( {{V_1} + {V_2}} \right)\rho g\]
\[ \Rightarrow 4 = \dfrac{m}{{10}} + \dfrac{{50 - m}}{{20}}\]
\[\Rightarrow 80 = 2m + 50 - m\]
\[ \Rightarrow m = 30kg\]
Thus the mass of the copper in the necklace \[ = 30kg\].
Hence the correct option is B.
Note: 1. Specific gravity is also called relative density. The specific gravity of liquids is usually measured by a hydrometer. Specific gravity is a dimensionless quantity as it is a ratio. Relative density is also used to quantify the buoyancy of a substance either in a fluid or in a gas.
2. In weight, changes occur only when mass and gravity changes. Whereas the density changes whenever the pressure and temperature of the object changes.
3. Volume is defined as the amount of space that is occupied by the object.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

