
What Is Acceleration Due To Gravity On Jupiter?
Answer
127.5k+ views
Hint:The universal gravitational constant is related to the attractive gravitational force between two bodies separated by a distance r. The acceleration due to gravity on earth is the acceleration experienced by anybody during free fall due to the attractive gravitational force of the earth's surface. It is not a universal constant. On earth, it is usually taken to be \[9.8{\rm{ }}m{s^{ - 2}}\].
Formula used:
Gravitational Force,
\[F = GMm/{r^2}\]
Where G = universal gravitational constant.
M= mass of the planet (earth)
m = mass of the lighter object
r = distance between the two objects
Acceleration due to gravity,
\[g = GM/{r^2}\]
where M= mass of the planet (earth)
r = radius of the planet
Complete step by step solution:
Given: mass of Jupiter = 319 times the mass of earth
Radius of Jupiter = 11.2 times the radius of earth
From Newton’s law of gravitation,
Force, \[F = GMm/{r^2}\]----- (1)
where G= universal gravitational constant = \[6.674 \times {10^{ - 11}}{m^3}k{g^{ - 1}}{s^{ - 2}}\]
Also, from Newton’s third law of motion,
\[F = mg\]------ (2)
where g = acceleration due to gravity on earth = \[9.8{\rm{ }}m{s^{ - 2}}\]
Equating (1) and (2)
\[g = GM/{r^2}\]------ (3)
Let \[\]\[M\], \[r\], \[{M_j}\] and \[{r_j}\] be masses and radii of earth and Jupiter respectively. Then according to the question,
\[{M_j} = 319M\]--(4) and \[{r_j} = 11.2r\]--- (5)
Using equation (3) to calculate \[{g_j}\]= acceleration due to gravity on Jupiter,
\[{g_j} = G{M_j}/{r^2}_j\]---- (6)
Substituting equations (4) and (5) in (6), we get,
\[{g_j} = G \times 319M/{(11.2r)^2}\]
\[\Rightarrow{g_j} = 2.54g\]
\[\Rightarrow {g_j} = 2.54 \times 9.8\]
\[\therefore {g_j} = 24.58\,m{s^{ - 2}}\]
Hence the acceleration due to gravity on Jupiter is \[{g_j} = 24.58\,m{s^{ - 2}}\].
Note: Although acceleration due to gravity is a constant, it is not a universal constant like universal gravitational constant, G. It varies on earth with change in reference surface such as when measured on a mountain or in the depths of water bodies like seas and oceans.
Formula used:
Gravitational Force,
\[F = GMm/{r^2}\]
Where G = universal gravitational constant.
M= mass of the planet (earth)
m = mass of the lighter object
r = distance between the two objects
Acceleration due to gravity,
\[g = GM/{r^2}\]
where M= mass of the planet (earth)
r = radius of the planet
Complete step by step solution:
Given: mass of Jupiter = 319 times the mass of earth
Radius of Jupiter = 11.2 times the radius of earth
From Newton’s law of gravitation,
Force, \[F = GMm/{r^2}\]----- (1)
where G= universal gravitational constant = \[6.674 \times {10^{ - 11}}{m^3}k{g^{ - 1}}{s^{ - 2}}\]
Also, from Newton’s third law of motion,
\[F = mg\]------ (2)
where g = acceleration due to gravity on earth = \[9.8{\rm{ }}m{s^{ - 2}}\]
Equating (1) and (2)
\[g = GM/{r^2}\]------ (3)
Let \[\]\[M\], \[r\], \[{M_j}\] and \[{r_j}\] be masses and radii of earth and Jupiter respectively. Then according to the question,
\[{M_j} = 319M\]--(4) and \[{r_j} = 11.2r\]--- (5)
Using equation (3) to calculate \[{g_j}\]= acceleration due to gravity on Jupiter,
\[{g_j} = G{M_j}/{r^2}_j\]---- (6)
Substituting equations (4) and (5) in (6), we get,
\[{g_j} = G \times 319M/{(11.2r)^2}\]
\[\Rightarrow{g_j} = 2.54g\]
\[\Rightarrow {g_j} = 2.54 \times 9.8\]
\[\therefore {g_j} = 24.58\,m{s^{ - 2}}\]
Hence the acceleration due to gravity on Jupiter is \[{g_j} = 24.58\,m{s^{ - 2}}\].
Note: Although acceleration due to gravity is a constant, it is not a universal constant like universal gravitational constant, G. It varies on earth with change in reference surface such as when measured on a mountain or in the depths of water bodies like seas and oceans.
Recently Updated Pages
JEE Main 2025 - Session 2 Registration Open | Exam Dates, Answer Key, PDF

Difference Between Vapor and Gas: JEE Main 2024

Area of an Octagon Formula - Explanation, and FAQs

Difference Between Solute and Solvent: JEE Main 2024

Absolute Pressure Formula - Explanation, and FAQs

Carbon Dioxide Formula - Definition, Uses and FAQs

Trending doubts
JEE Main Login 2045: Step-by-Step Instructions and Details

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Course 2025: Get All the Relevant Details

JEE Main Chemistry Question Paper with Answer Keys and Solutions

Other Pages
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Oscillation Class 11 Notes: CBSE Physics Chapter 13

NCERT Solutions for Class 11 Physics Chapter 10 Thermal Properties of Matter

NCERT Solutions for Class 11 Physics Chapter 8 Mechanical Properties of Solids

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

NCERT Solutions for Class 11 Physics Chapter 14 Waves
