
An air bubble in glass slab $\left( {\mu = 1.5} \right)$ from one side is $6\,cm$ and from the other side is $4\,cm$. The thickness of glass slab is:
(A) $10\,cm$
(B) $6.67\,cm$
(C) $15\,cm$
(D) none of these
Answer
232.8k+ views
Hint: The thickness of the slab is determined by using the refractive index formula. By using the apparent depth of the first side, the real depth is determined, for the apparent depth of the second side, the real depth is taken as the difference of the thickness and the real depth, then the thickness is determined.
Useful formula
The refractive index of the glass slab is given by,
$\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}$
Where, $\mu $ is the refractive index of the glass slab.
Complete step by step solution
Given that,
The refractive index of the glass slab is, $\mu = 1.5$,
The apparent depth from first side is, $6\,cm$
The apparent depth from second side is, $4\,cm$
Assume that the real depth be $x$, then
The refractive index of the glass slab is given by,
$\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}\,..................\left( 1 \right)$
By substituting the real depth and apparent depth in the above equation (1), then the above equation (1) is written as,
$\mu = \dfrac{x}{6}$
By substituting the refractive index value in the above equation, then the above equation is written as,
$1.5 = \dfrac{x}{6}$
By rearranging the terms, then the above equation is written as,
$x = 1.5 \times 6$
On multiplying the terms in the above equation, then
$x = 9$
Now, using the refractive index formula for second side, then assume that the real depth is $t - x$, then
$\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}$
By substituting the refractive index, real depth and apparent depth in the above equation, then
\[1.5 = \dfrac{{t - x}}{4}\]
Now substituting the value of $x$ in the above equation, then
\[1.5 = \dfrac{{t - 9}}{4}\]
By rearranging the terms, then the above equation is written as,
\[t - 9 = 1.5 \times 4\]
On multiplying the terms in the above equation, then
\[t - 9 = 6\]
By keeping the term $t$ in one side, then
\[t = 6 + 9\]
By adding the terms in the above equation, then
$t = 15\,cm$
Hence, the option (C) is the correct answer.
Note: The refractive index is directly proportional to the real depth and the refractive index is inversely proportional to the apparent depth. As the refractive index increases when the real depth increases and the apparent depth decreases. As the refractive index decreases when the real depth decreases and the apparent depth increases.
Useful formula
The refractive index of the glass slab is given by,
$\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}$
Where, $\mu $ is the refractive index of the glass slab.
Complete step by step solution
Given that,
The refractive index of the glass slab is, $\mu = 1.5$,
The apparent depth from first side is, $6\,cm$
The apparent depth from second side is, $4\,cm$
Assume that the real depth be $x$, then
The refractive index of the glass slab is given by,
$\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}\,..................\left( 1 \right)$
By substituting the real depth and apparent depth in the above equation (1), then the above equation (1) is written as,
$\mu = \dfrac{x}{6}$
By substituting the refractive index value in the above equation, then the above equation is written as,
$1.5 = \dfrac{x}{6}$
By rearranging the terms, then the above equation is written as,
$x = 1.5 \times 6$
On multiplying the terms in the above equation, then
$x = 9$
Now, using the refractive index formula for second side, then assume that the real depth is $t - x$, then
$\mu = \dfrac{{{\text{Real depth}}}}{{{\text{Apparent depth}}}}$
By substituting the refractive index, real depth and apparent depth in the above equation, then
\[1.5 = \dfrac{{t - x}}{4}\]
Now substituting the value of $x$ in the above equation, then
\[1.5 = \dfrac{{t - 9}}{4}\]
By rearranging the terms, then the above equation is written as,
\[t - 9 = 1.5 \times 4\]
On multiplying the terms in the above equation, then
\[t - 9 = 6\]
By keeping the term $t$ in one side, then
\[t = 6 + 9\]
By adding the terms in the above equation, then
$t = 15\,cm$
Hence, the option (C) is the correct answer.
Note: The refractive index is directly proportional to the real depth and the refractive index is inversely proportional to the apparent depth. As the refractive index increases when the real depth increases and the apparent depth decreases. As the refractive index decreases when the real depth decreases and the apparent depth increases.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

