Answer
77.7k+ views
Hint: At first, we will write the electronic configurations of all the given atomic numbers.
Then, we will try to match those electronic configurations with the electronic configuration of nearest Noble gas atom.
Then we can easily find out the element which will combine with the element having atomic number \[19.\]
Complete step by step answer:
Electronic configuration of atomic number\[ - 19 - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^6}{\text{4}}{{\text{s}}^1}\]
Electronic configuration of atomic number\[ - 17{\text{ }}\left( A \right) - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^5}\]
Electronic configuration of atomic number\[ - 11{\text{ }}\left( B \right) - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^1}\]
Electronic configuration of atomic number\[ - 18{\text{ }}\left( C \right) - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^6}\]
Electronic configuration of atomic number\[ - 20{\text{ }}\left( D \right) - \] \[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^6}{\text{4}}{{\text{s}}^2}\]
So, from the electronic configurations, we can see that the atomic number\[ - 18{\text{ }}\left( {option{\text{ }} - C} \right)\] is the electronic configuration of a noble gas. So, this is a stable electronic configuration.
This noble gas is the nearest noble gas of both the atomicnumbers\[ - 17{\text{ }}\left( {option{\text{ }} - A} \right){\text{ }}and{\text{ }}20{\text{ }}\left( {option - D} \right)\] and also the atomic number\[ - 19.\]
So, all the atoms having atomic numbers\[ - 17\]\[\left( {option{\text{ }} - A} \right){\text{ }}and{\text{ }}20{\text{ }}\left( {option - D} \right)\]andatomic number-\[19\] will try to attain the stable electronic configuration of atomic number\[ - 18{\text{ }}\left( {option - C} \right)\]
Now, the atomic number\[ - 19\] has one excess electron than the atomic number\[ - 18{\text{ }}\left( {option{\text{ }} - C} \right)\] and the atomic number\[ - 17\left( {option{\text{ }} - A} \right)\] has one less electron than the atomic number \[18{\text{ }}\left( {option{\text{ }} - C} \right).\]
So, these two \[\left( {atomic{\text{ }}number{\text{ }}19{\text{ }}andatomic{\text{ }}number{\text{ }}17} \right)\] will combine most likely.
So, option-\[A\] is the correct option.
Note:
1. We should remember that all the elements try to attain a stable electronic configuration of it’s nearest noble gas.
2. If the situation was given for atomic number\[ - 16,\] it will most likely combine with the atomic number\[ - 20.\]
3. We have to remember that all the atoms try to fulfil its valence shell with electrons.
Then, we will try to match those electronic configurations with the electronic configuration of nearest Noble gas atom.
Then we can easily find out the element which will combine with the element having atomic number \[19.\]
Complete step by step answer:
Electronic configuration of atomic number\[ - 19 - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^6}{\text{4}}{{\text{s}}^1}\]
Electronic configuration of atomic number\[ - 17{\text{ }}\left( A \right) - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^5}\]
Electronic configuration of atomic number\[ - 11{\text{ }}\left( B \right) - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^1}\]
Electronic configuration of atomic number\[ - 18{\text{ }}\left( C \right) - \]\[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^6}\]
Electronic configuration of atomic number\[ - 20{\text{ }}\left( D \right) - \] \[{\text{1}}{{\text{s}}^2}{\text{2}}{{\text{s}}^2}{\text{2}}{{\text{p}}^6}{\text{3}}{{\text{s}}^2}{\text{3}}{{\text{p}}^6}{\text{4}}{{\text{s}}^2}\]
So, from the electronic configurations, we can see that the atomic number\[ - 18{\text{ }}\left( {option{\text{ }} - C} \right)\] is the electronic configuration of a noble gas. So, this is a stable electronic configuration.
This noble gas is the nearest noble gas of both the atomicnumbers\[ - 17{\text{ }}\left( {option{\text{ }} - A} \right){\text{ }}and{\text{ }}20{\text{ }}\left( {option - D} \right)\] and also the atomic number\[ - 19.\]
So, all the atoms having atomic numbers\[ - 17\]\[\left( {option{\text{ }} - A} \right){\text{ }}and{\text{ }}20{\text{ }}\left( {option - D} \right)\]andatomic number-\[19\] will try to attain the stable electronic configuration of atomic number\[ - 18{\text{ }}\left( {option - C} \right)\]
Now, the atomic number\[ - 19\] has one excess electron than the atomic number\[ - 18{\text{ }}\left( {option{\text{ }} - C} \right)\] and the atomic number\[ - 17\left( {option{\text{ }} - A} \right)\] has one less electron than the atomic number \[18{\text{ }}\left( {option{\text{ }} - C} \right).\]
So, these two \[\left( {atomic{\text{ }}number{\text{ }}19{\text{ }}andatomic{\text{ }}number{\text{ }}17} \right)\] will combine most likely.
So, option-\[A\] is the correct option.
Note:
1. We should remember that all the elements try to attain a stable electronic configuration of it’s nearest noble gas.
2. If the situation was given for atomic number\[ - 16,\] it will most likely combine with the atomic number\[ - 20.\]
3. We have to remember that all the atoms try to fulfil its valence shell with electrons.
Recently Updated Pages
Name the scale on which the destructive energy of an class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write an article on the need and importance of sports class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Choose the one which best expresses the meaning of class 9 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What does a hydrometer consist of A A cylindrical stem class 9 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A motorcyclist of mass m is to negotiate a curve of class 9 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)