
An organic liquid A, containing C,H and O, has a pleasant odour with the boiling point of ${78^ \circ }C$. Upon boiling A with conc. ${H_2}S{O_4}$, a colourless gas B is produced which decolourise bromine water and alkaline $KMn{O_4}$. The organic liquid A is:
(A) $C{H_3}OH$
(B) ${C_2}{H_5}CHO$
(C) ${C_2}{H_6}$
(D) ${C_2}{H_5}OH$
Answer
232.8k+ views
Hint: The compounds that have alcohol group (-OH) may have pleasant odour. All the compounds that have unsaturation in their structure decolourised both bromine water and alkaline potassium permanganate solution.
Complete step by step solution:
We will see all the characteristics of the compound given in the question and find which compound gives that.
- It is given that the organic liquid having C, H and O atoms has a pleasant odour. So, the functional group present in the compound can be alcohol group (-OH).
- It is given that the compound gives a colourless gas upon boiling it with concentrated sulphuric acid. Out of all the given compounds, the one which gives a gas upon an easy reaction with concentrated sulphuric acid is ethanol. The reaction is,
\[{C_2}{H_5}OH\xrightarrow[{ - {H_2}O}]{{{H_2}S{O_4}}}{H_2}C = C{H_2}\]
Thus, we can see that ethene is produced by the dehydration reaction of ethanol. We know that concentrated sulphuric acid is a strong dehydrating agent. Ethene is a colourless gas.
- More importantly ethene decolourise the bromine water as well as alkaline $KMn{O_4}$ solution. It gives this reaction because unsaturation is present in ethene as a C-C double bond is there. So, any compound that has unsaturation gives a decolourization reaction with bromine water and potassium permanganate.
- The boiling point of ethanol is also ${78^ \circ }C$.
Thus, we can say that the compound A is ethanol (${C_2}{H_5}OH$).
So, the correct answer is (D).
Note: Any alcohol when allowed to react with concentrated sulphuric acid will lose a molecule of water and form a C-C double bond. This reaction involves loss of a water molecule from the substrate so it is also called dehydration reaction.
Complete step by step solution:
We will see all the characteristics of the compound given in the question and find which compound gives that.
- It is given that the organic liquid having C, H and O atoms has a pleasant odour. So, the functional group present in the compound can be alcohol group (-OH).
- It is given that the compound gives a colourless gas upon boiling it with concentrated sulphuric acid. Out of all the given compounds, the one which gives a gas upon an easy reaction with concentrated sulphuric acid is ethanol. The reaction is,
\[{C_2}{H_5}OH\xrightarrow[{ - {H_2}O}]{{{H_2}S{O_4}}}{H_2}C = C{H_2}\]
Thus, we can see that ethene is produced by the dehydration reaction of ethanol. We know that concentrated sulphuric acid is a strong dehydrating agent. Ethene is a colourless gas.
- More importantly ethene decolourise the bromine water as well as alkaline $KMn{O_4}$ solution. It gives this reaction because unsaturation is present in ethene as a C-C double bond is there. So, any compound that has unsaturation gives a decolourization reaction with bromine water and potassium permanganate.
- The boiling point of ethanol is also ${78^ \circ }C$.
Thus, we can say that the compound A is ethanol (${C_2}{H_5}OH$).
So, the correct answer is (D).
Note: Any alcohol when allowed to react with concentrated sulphuric acid will lose a molecule of water and form a C-C double bond. This reaction involves loss of a water molecule from the substrate so it is also called dehydration reaction.
Recently Updated Pages
Types of Solutions in Chemistry: Explained Simply

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions (2025-26)

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 4 The d and f Block Elements (2025-26)

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules (2025-26)

