Answer
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Hint: The compounds that have alcohol group (-OH) may have pleasant odour. All the compounds that have unsaturation in their structure decolourised both bromine water and alkaline potassium permanganate solution.
Complete step by step solution:
We will see all the characteristics of the compound given in the question and find which compound gives that.
- It is given that the organic liquid having C, H and O atoms has a pleasant odour. So, the functional group present in the compound can be alcohol group (-OH).
- It is given that the compound gives a colourless gas upon boiling it with concentrated sulphuric acid. Out of all the given compounds, the one which gives a gas upon an easy reaction with concentrated sulphuric acid is ethanol. The reaction is,
\[{C_2}{H_5}OH\xrightarrow[{ - {H_2}O}]{{{H_2}S{O_4}}}{H_2}C = C{H_2}\]
Thus, we can see that ethene is produced by the dehydration reaction of ethanol. We know that concentrated sulphuric acid is a strong dehydrating agent. Ethene is a colourless gas.
- More importantly ethene decolourise the bromine water as well as alkaline $KMn{O_4}$ solution. It gives this reaction because unsaturation is present in ethene as a C-C double bond is there. So, any compound that has unsaturation gives a decolourization reaction with bromine water and potassium permanganate.
- The boiling point of ethanol is also ${78^ \circ }C$.
Thus, we can say that the compound A is ethanol (${C_2}{H_5}OH$).
So, the correct answer is (D).
Note: Any alcohol when allowed to react with concentrated sulphuric acid will lose a molecule of water and form a C-C double bond. This reaction involves loss of a water molecule from the substrate so it is also called dehydration reaction.
Complete step by step solution:
We will see all the characteristics of the compound given in the question and find which compound gives that.
- It is given that the organic liquid having C, H and O atoms has a pleasant odour. So, the functional group present in the compound can be alcohol group (-OH).
- It is given that the compound gives a colourless gas upon boiling it with concentrated sulphuric acid. Out of all the given compounds, the one which gives a gas upon an easy reaction with concentrated sulphuric acid is ethanol. The reaction is,
\[{C_2}{H_5}OH\xrightarrow[{ - {H_2}O}]{{{H_2}S{O_4}}}{H_2}C = C{H_2}\]
Thus, we can see that ethene is produced by the dehydration reaction of ethanol. We know that concentrated sulphuric acid is a strong dehydrating agent. Ethene is a colourless gas.
- More importantly ethene decolourise the bromine water as well as alkaline $KMn{O_4}$ solution. It gives this reaction because unsaturation is present in ethene as a C-C double bond is there. So, any compound that has unsaturation gives a decolourization reaction with bromine water and potassium permanganate.
- The boiling point of ethanol is also ${78^ \circ }C$.
Thus, we can say that the compound A is ethanol (${C_2}{H_5}OH$).
So, the correct answer is (D).
Note: Any alcohol when allowed to react with concentrated sulphuric acid will lose a molecule of water and form a C-C double bond. This reaction involves loss of a water molecule from the substrate so it is also called dehydration reaction.
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