
Define acceleration and state SI unit for motion along a straight line, when do we consider the acceleration to be
(A) Positive
B. Negative
Give example of a body in uniform acceleration
Answer
131.7k+ views
Hint Generally, positive means positive graph we will get and negative means negative graph we will get so here something it’s increasing or decreasing
As it relates to the velocity so as it increases it becomes faster so accelerates
Complete Step by step solution
First of all we need to think that what do you generally mean by acceleration
When the velocity of a body is increasing the body is said to be accelerating
Acceleration of the body is defined as the rate of change of its velocity with time
Acceleration = change in velocity / time taken for change $a = \dfrac{{v - u}}{t}$
$a = \dfrac{{v - u}}{t}$
Where a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
SI unit of acceleration is $m/s_{}^2$$m/s_{}^2$
It is a vector quantity .
So coming to the next part:
There are two types of acceleration positive and negative
If the velocity of a body increases the acceleration is positive
And if the velocity of a body decreases acceleration is negative
Negative acceleration or deceleration is also measured in the same way as positive
Example
1. A ball being hit by the tennis racket both the ball’s speed and direction is changing
Now example of uniform acceleration
2. THE MOTION OF FREELY FALLING BODY
3. The motion of bicycle going down the slope when the rider is not pedalling
Additional information
When a body is moving with the uniform velocity its acceleration will be zero
A body is said to be uniform acceleration if it travels in a straight line and velocity increases by equal amounts in equal interval of time
Note
First I need to understand the trick that is the relation of positive and negative increasing and decreasing and uniform means everything needs to be equal and perfect.
As it relates to the velocity so as it increases it becomes faster so accelerates
Complete Step by step solution
First of all we need to think that what do you generally mean by acceleration
When the velocity of a body is increasing the body is said to be accelerating
Acceleration of the body is defined as the rate of change of its velocity with time
Acceleration = change in velocity / time taken for change $a = \dfrac{{v - u}}{t}$
$a = \dfrac{{v - u}}{t}$
Where a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
SI unit of acceleration is $m/s_{}^2$$m/s_{}^2$
It is a vector quantity .
So coming to the next part:
There are two types of acceleration positive and negative
If the velocity of a body increases the acceleration is positive
And if the velocity of a body decreases acceleration is negative
Negative acceleration or deceleration is also measured in the same way as positive
Example
1. A ball being hit by the tennis racket both the ball’s speed and direction is changing
Now example of uniform acceleration
2. THE MOTION OF FREELY FALLING BODY
3. The motion of bicycle going down the slope when the rider is not pedalling
Additional information
When a body is moving with the uniform velocity its acceleration will be zero
A body is said to be uniform acceleration if it travels in a straight line and velocity increases by equal amounts in equal interval of time
Note
First I need to understand the trick that is the relation of positive and negative increasing and decreasing and uniform means everything needs to be equal and perfect.
Recently Updated Pages
A steel rail of length 5m and area of cross section class 11 physics JEE_Main

At which height is gravity zero class 11 physics JEE_Main

A nucleus of mass m + Delta m is at rest and decays class 11 physics JEE_MAIN

A wave is travelling along a string At an instant the class 11 physics JEE_Main

The length of a conductor is halved its conductivity class 11 physics JEE_Main

The x t graph of a particle undergoing simple harmonic class 11 physics JEE_MAIN

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

Degree of Dissociation and Its Formula With Solved Example for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Clemmenson and Wolff Kishner Reductions for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line

NCERT Solutions for Class 11 Physics Chapter 3 Motion In A Plane

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement

NCERT Solutions for Class 11 Physics Chapter 5 Work Energy and Power
