
What is the dimensional formula for magnetic flux densities?
Answer
221.4k+ views
Hint: The above problem can be resolved by using the concepts and applications of the dimensional formulas. The dimensional formula for the magnetic flux density can be obtained by the mathematical relation for the magnetic flux density. The magnetic flux density is determined by taking the ratio of the magnetic flux and the region's volume taken into consideration. Then the corresponding values are substituted, and the final result is obtained.
Complete Step by Step Solution:
A dimensional formula represents an equation, which gives the relation between fundamental units and derived units in terms of dimensions.
The length, mass and time are taken as three base dimensions and are represented by letters L, M, T respectively.
Magnetic flux is a measure of the quantity of magnetism, being the total number of magnetic lines of force passing through a specified area in a magnetic field. Magnetic flux through a plane of area $A$ placed in a uniform magnetic field $B$ can be written as ${\varphi _B} = B \cdot A = BA\cos \theta $.
The dimensional formula of area is $A = \left[ {{M^0}{L^2}{T^0}} \right]$ and
The dimensional formula of magnetic field is $B = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$ since, $B = \dfrac{{{\text{Force}}}}{{{\text{Charge} \times \text{Velocity}}}} = \dfrac{{\left[ {{M^1}{L^1}{T^{ - 2}}} \right]}}{{\left[ {{M^0}{L^0}{T^0}{I^1}} \right]\left[ {{L^1}{T^{ - 1}}} \right]}} = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$.
Since $\cos \theta $ is a number, it has no dimensions.
Thus, the dimensional formula of magnetic flux is ${\varphi _B} = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]\left[ {{L^2}} \right] = \left[ {{M^1}{L^2}{T^{ - 2}}{I^{ - 1}}} \right]$
Magnetic Flux Density is the amount of magnetic flux through unit area taken perpendicular to direction of magnetic flux. Mathematically, $b = \dfrac{{{\varphi _B}}}{A}$.
Thus, the dimensional formula of magnetic flux density is $b = \dfrac{{{\varphi _B}}}{A} = \dfrac{{\left[ {{M^1}{L^2}{T^{ - 2}}{I^{ - 1}}} \right]}}{{\left[ {{L^2}} \right]}} = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$.
Note: Flux Density ($b$) is related to Magnetic Field ($B$) by $b = \mu B$ where $\mu $ is the permeability of the medium (material) where we are measuring the fields.
The permeability of the medium is a constant and has no dimensions.
Thus the dimensional formula of magnetic flux density is the same as that of the magnetic field $B$, which is given by, $B = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$.
Complete Step by Step Solution:
A dimensional formula represents an equation, which gives the relation between fundamental units and derived units in terms of dimensions.
The length, mass and time are taken as three base dimensions and are represented by letters L, M, T respectively.
Magnetic flux is a measure of the quantity of magnetism, being the total number of magnetic lines of force passing through a specified area in a magnetic field. Magnetic flux through a plane of area $A$ placed in a uniform magnetic field $B$ can be written as ${\varphi _B} = B \cdot A = BA\cos \theta $.
The dimensional formula of area is $A = \left[ {{M^0}{L^2}{T^0}} \right]$ and
The dimensional formula of magnetic field is $B = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$ since, $B = \dfrac{{{\text{Force}}}}{{{\text{Charge} \times \text{Velocity}}}} = \dfrac{{\left[ {{M^1}{L^1}{T^{ - 2}}} \right]}}{{\left[ {{M^0}{L^0}{T^0}{I^1}} \right]\left[ {{L^1}{T^{ - 1}}} \right]}} = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$.
Since $\cos \theta $ is a number, it has no dimensions.
Thus, the dimensional formula of magnetic flux is ${\varphi _B} = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]\left[ {{L^2}} \right] = \left[ {{M^1}{L^2}{T^{ - 2}}{I^{ - 1}}} \right]$
Magnetic Flux Density is the amount of magnetic flux through unit area taken perpendicular to direction of magnetic flux. Mathematically, $b = \dfrac{{{\varphi _B}}}{A}$.
Thus, the dimensional formula of magnetic flux density is $b = \dfrac{{{\varphi _B}}}{A} = \dfrac{{\left[ {{M^1}{L^2}{T^{ - 2}}{I^{ - 1}}} \right]}}{{\left[ {{L^2}} \right]}} = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$.
Note: Flux Density ($b$) is related to Magnetic Field ($B$) by $b = \mu B$ where $\mu $ is the permeability of the medium (material) where we are measuring the fields.
The permeability of the medium is a constant and has no dimensions.
Thus the dimensional formula of magnetic flux density is the same as that of the magnetic field $B$, which is given by, $B = \left[ {{M^1}{T^{ - 2}}{I^{ - 1}}} \right]$.
Recently Updated Pages
Uniform Acceleration Explained: Formula, Examples & Graphs

JEE Main 2022 (July 26th Shift 1) Physics Question Paper with Answer Key

JEE Main 2022 (June 26th Shift 2) Chemistry Question Paper with Answer Key

Apparent Frequency Explained: Formula, Uses & Examples

JEE Main 2023 (January 30th Shift 2) Chemistry Question Paper with Answer Key

JEE Main 2023 (April 15th Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

