Draw the distance-time graph of a body moving with a constant speed of $5m/s$ for$10s$.
Answer
Verified
123k+ views
Hint: Speed may be a measure of how quickly an object moves from one place to another. It’s equal to the distance traveled divided by the time. It’s potential to search out any of those 3 values using the opposite two.
Formula used:
Speed,
$ \Rightarrow S = \dfrac{D}{T}$
Here, $S$ is the speed, $D$ is the distance, and $T$ is the time.
Complete step by step solution:
Here we have to plot the graph of the distance-time. And it is given that we are a body which is moving with constant speed and having some time which is given in the question.
Now we will calculate the distance the body covers. Since we have to plot the graph for the distance that’s why we have to first calculate the distance.
By using the above formula,
$ \Rightarrow S = \dfrac{D}{T}$
It can also be written as
$ \Rightarrow D = S \times T$
Now we will put the values.
On putting the values, we get
$ \Rightarrow D = 5m/s \times 10s$
On solving the above lines we will get,
$ \Rightarrow D = 50m/{s^2}$
Now for this, we will plot the graph.
So the distance-time graph for the constant speed is shown below, distance is changing with the constant speed and time. Hence the graph will be a straight line having the slope in it.
The above graph is the distance-time graph of a body which is moving with the constant speed of $5m/s$ and having the time is $10s$.
Note: If an object moves on a line, the distance traveled is described by a distance-time graph. In a distance-time graph, the gradient of the road is up to the speed of the object. The bigger the gradient (and the steeper the line) the quicker the thing is moving.
Formula used:
Speed,
$ \Rightarrow S = \dfrac{D}{T}$
Here, $S$ is the speed, $D$ is the distance, and $T$ is the time.
Complete step by step solution:
Here we have to plot the graph of the distance-time. And it is given that we are a body which is moving with constant speed and having some time which is given in the question.
Now we will calculate the distance the body covers. Since we have to plot the graph for the distance that’s why we have to first calculate the distance.
By using the above formula,
$ \Rightarrow S = \dfrac{D}{T}$
It can also be written as
$ \Rightarrow D = S \times T$
Now we will put the values.
On putting the values, we get
$ \Rightarrow D = 5m/s \times 10s$
On solving the above lines we will get,
$ \Rightarrow D = 50m/{s^2}$
Now for this, we will plot the graph.
So the distance-time graph for the constant speed is shown below, distance is changing with the constant speed and time. Hence the graph will be a straight line having the slope in it.
The above graph is the distance-time graph of a body which is moving with the constant speed of $5m/s$ and having the time is $10s$.
Note: If an object moves on a line, the distance traveled is described by a distance-time graph. In a distance-time graph, the gradient of the road is up to the speed of the object. The bigger the gradient (and the steeper the line) the quicker the thing is moving.
Recently Updated Pages
The ratio of the diameters of two metallic rods of class 11 physics JEE_Main
What is the difference between Conduction and conv class 11 physics JEE_Main
Mark the correct statements about the friction between class 11 physics JEE_Main
Find the acceleration of the wedge towards the right class 11 physics JEE_Main
A standing wave is formed by the superposition of two class 11 physics JEE_Main
Derive an expression for work done by the gas in an class 11 physics JEE_Main
Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Login 2045: Step-by-Step Instructions and Details
Class 11 JEE Main Physics Mock Test 2025
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes: CBSE Physics Chapter 1
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line