Draw the typical input and output characteristics of a $n - p - n$ transistor in $CE$ configuration. Show how these characteristics can be used to determine
(a) the input resistance ( ${r_i}$ ) and
(b) current amplification factor $\left( \beta \right)$ .
Answer
Verified
122.7k+ views
Hint: The $n - p - n$ transistor has the input, output and the transfer characteristics. Draw the input characteristics between base current and base emitter voltage and the output characteristics between the collector current and the common emitter voltage.
Complete step by step solution:
(a) The input resistance is also known as input impedance. It is defined as the ratio of the changes in the base emitter voltage to the corresponding change in the base current at a given particular common emitter voltage in the transistor.
The formula of the input impedance is given by
${r_i} = \dfrac{{\Delta {V_{BE}}}}{{\Delta {I_B}}}$ ( at a given ${V_{CE}}$ )
(b) The term current amplification factor is also known as the current gain. It is obtained by dividing the small change in the collector current to that of the corresponding change in the base current of the transistor at constant common emitter voltage.
The formula of the current amplification factor is given by
$\beta = \dfrac{{\Delta {I_C}}}{{\Delta {I_B}}}$ ( at a given ${V_{CE}}$ )
The following graph represents the input characteristics of the $n - p - n$ transistor. It shows that to a certain point, when the base current increases the base emitter voltage remains the same.
The following graph shows the output characteristics of the $n - p - n$ transistor. It includes the cut off, active and the saturated regions of the base current where the common emitter voltage is constant.
Note: In the $n - p - n$ transistor, the $P$ - type of the semiconductor is made connected between the $N$ - type of the semiconductor. It is most commonly used and it looks like the $PN$ junction diode connected back to back. In this transistor, the electron transfers from the base to the collector.
Complete step by step solution:
(a) The input resistance is also known as input impedance. It is defined as the ratio of the changes in the base emitter voltage to the corresponding change in the base current at a given particular common emitter voltage in the transistor.
The formula of the input impedance is given by
${r_i} = \dfrac{{\Delta {V_{BE}}}}{{\Delta {I_B}}}$ ( at a given ${V_{CE}}$ )
(b) The term current amplification factor is also known as the current gain. It is obtained by dividing the small change in the collector current to that of the corresponding change in the base current of the transistor at constant common emitter voltage.
The formula of the current amplification factor is given by
$\beta = \dfrac{{\Delta {I_C}}}{{\Delta {I_B}}}$ ( at a given ${V_{CE}}$ )
The following graph represents the input characteristics of the $n - p - n$ transistor. It shows that to a certain point, when the base current increases the base emitter voltage remains the same.
The following graph shows the output characteristics of the $n - p - n$ transistor. It includes the cut off, active and the saturated regions of the base current where the common emitter voltage is constant.
Note: In the $n - p - n$ transistor, the $P$ - type of the semiconductor is made connected between the $N$ - type of the semiconductor. It is most commonly used and it looks like the $PN$ junction diode connected back to back. In this transistor, the electron transfers from the base to the collector.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Concept of CP and CV of Gas - Important Concepts and Tips for JEE
Trending doubts
JEE Mains 2025: Check Important Dates, Syllabus, Exam Pattern, Fee and Updates
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Chemistry Question Paper with Answer Keys and Solutions
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
JEE Main Chemistry Exam Pattern 2025
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11
Electric field due to uniformly charged sphere class 12 physics JEE_Main