During the preparation of phenol from benzene sulfonic acid, which of the following reagents is to be used?
(A) NaOH
(B) $NaHS{{O}_{4}}$
(C) $N{{a}_{2}}S{{O}_{4}}$
(D) $NaCl$
Answer
Verified
120k+ views
Hint: Benzene sulphonic acid which is a conjugate base of benzene sulphonate is an organosulfur compound with chemical formula ${{C}_{6}}{{H}_{6}}{{O}_{3}}S$and is the simplest aromatic sulfonic acid. It is a strong acid and dissociates fully in water.
Step by step answer:
-Benzene sulphonic acid is obtained by reacting benzene with oleum. The formed benzene sulphonic acid, when treated with molten sodium hydroxide at high temperature, favours the formation of sodium phenoxide ion which on further acidification gives phenol.
So, the correct answer is option A.
Additional information:
-Phenol can be prepared by many other processes which are described below-
(i) From haloarenes- Chlorobenzene which is formed by the monosubstitution of the benzene ring is an example of haloarene. When chlorobenzene is fused with sodium hydroxide at 626K and 20atm, sodium phenoxide is formed which on acidification gives phenol.
(ii) From Diazonium salts- Diazonium salts are obtained when an aromatic primary amine is treated with nitrous acid $(NaN{{O}_{2}}+HCl)$at about 273-278K. These diazonium salts are chemically highly reactive. The diazonium salts upon warming with water hydrolyzes to phenols.
(iii) From cumene- Cumene is an organic compound produced by Friedel Crafts alkylation of benzene with propylene. Oxidation of cumene in the presence of air gives hydroperoxide which on further treatment with dilute acids gives phenol along with acetone as side by-products in large quantities. Hence phenols formed by this method need purifications.
Note: The alkali metal salt of benzene sulphonic acid used in the industrial production of phenol involves the presence of phenoxide salt and produced a lot of water and side products. This process is sometimes known as alkaline fusion. Now, this process is replaced by the Hock process for the production of phenol as it produces less waste.
Step by step answer:
-Benzene sulphonic acid is obtained by reacting benzene with oleum. The formed benzene sulphonic acid, when treated with molten sodium hydroxide at high temperature, favours the formation of sodium phenoxide ion which on further acidification gives phenol.
So, the correct answer is option A.
Additional information:
-Phenol can be prepared by many other processes which are described below-
(i) From haloarenes- Chlorobenzene which is formed by the monosubstitution of the benzene ring is an example of haloarene. When chlorobenzene is fused with sodium hydroxide at 626K and 20atm, sodium phenoxide is formed which on acidification gives phenol.
(ii) From Diazonium salts- Diazonium salts are obtained when an aromatic primary amine is treated with nitrous acid $(NaN{{O}_{2}}+HCl)$at about 273-278K. These diazonium salts are chemically highly reactive. The diazonium salts upon warming with water hydrolyzes to phenols.
(iii) From cumene- Cumene is an organic compound produced by Friedel Crafts alkylation of benzene with propylene. Oxidation of cumene in the presence of air gives hydroperoxide which on further treatment with dilute acids gives phenol along with acetone as side by-products in large quantities. Hence phenols formed by this method need purifications.
Note: The alkali metal salt of benzene sulphonic acid used in the industrial production of phenol involves the presence of phenoxide salt and produced a lot of water and side products. This process is sometimes known as alkaline fusion. Now, this process is replaced by the Hock process for the production of phenol as it produces less waste.
Recently Updated Pages
Classification of Drugs Based on Pharmacological Effect, Drug Action
Types of Solutions - Solution in Chemistry
Difference Between Alcohol and Phenol
JEE Main Participating Colleges 2024 - A Complete List of Top Colleges
JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips
Sign up for JEE Main 2025 Live Classes - Vedantu
Trending doubts
JEE Mains 2025: Check Important Dates, Syllabus, Exam Pattern, Fee and Updates
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Chemistry Question Paper with Answer Keys and Solutions
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main Chemistry Online Mock Test for Class 12
JEE Main Chemistry Exam Pattern 2025
Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes
NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions
NCERT Solutions for Class 12 Chemistry Chapter 7 Alcohol Phenol and Ether
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
NCERT Solutions for Class 12 Chemistry Chapter 9 Amines