Hint: Compare the given equation of parabola with the standard form and find the values of $x_0$, $y_0$ and a. Substitute these values in focus of parabola $(x_0+a, y_0)$ to find the required solution.
Complete step by step answer:
As, we know that the standard equation of parabola is ${\left( {y - {y_0}} \right)^2} = 4a\left( {x - {x_0}} \right)$. In which,
$\Rightarrow$ Vertex = $(x_0,y_0)$ and,
$ \Rightarrow$ Focus of parabola is $(x_0+a, y_0)$
$ \Rightarrow {\left( {y - 2} \right)^2} = 20\left( {x + 3} \right)$..............................(1)
Comparing equation (1) with standard equation of parabola we get,
$\Rightarrow {x_0} = - 3,{\text{ }}{y_0} = 2$ and a = 5
So, focus of the parabola in equation 1 will be,
$\Rightarrow {\text{focus}} = \left( { - 3 + 5,2} \right) = \left( {2,2} \right)$
Hence the correct option for the question will be c.
NOTE: - Whenever this type of question is given then compare ${x_0}{\text{, }}{y_0}$ and a with the standard equation of parabola. And then find the required parameter by putting values.