Answer
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Hint:The numerical problem is from the current electricity part of physics. We can apply electric power and equivalent resistance concepts to solve the problem.
Formula used:
For maximum power, the equivalent resistance should be equal to internal resistance. That is,
$r = {R_E}$
Where ${R_E}$ = equivalent resistant and r = internal resistance.
Equivalent resistance for a series resistance circuit:
${R_E} = {R_1} + {R_2} + {R_3}$
Where ${R_E}$= equivalent resistance and ${R_1},{R_2},{R_3}$ = component resistance.
Equivalent resistance for a parallel resistance circuit:
$\dfrac{1}{{{R_E}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}} + \dfrac{1}{{{R_3}}}$
Where ${R_E}$= equivalent resistance and ${R_1},{R_2},{R_3}$ = component resistance.
Complete step by step solution:
In the triangle part of the circuit, the three sides have two resistances in a series connection. Their equivalent resistance will be ${R_E} = R + R = 2R$. The circuit diagram will be
The equivalent resistance for the three parallel combinations in the circuit will become,
$\dfrac{1}{{{R_E}}} = \dfrac{1}{R} + \dfrac{1}{{2R}} = \dfrac{3}{{2R}} \\
\Rightarrow {R_E} = \dfrac{{2R}}{3}$
The equivalent resistance for the three-series connection is,
${R_E} = \dfrac{{2R}}{3} + \dfrac{{2R}}{3} = \dfrac{{4R}}{3}$
The equivalent resistance for the final parallel connection is,
${R_E} = \dfrac{{\dfrac{{2R}}{3} \times \dfrac{{4R}}{3}}}{{\dfrac{{2R}}{3} + \dfrac{{4R}}{3}}} = \dfrac{{4R}}{9}$
Hence, the correct option is option B.
Additional Information: Resistance blocks the flow of current. The S.I. unit of resistance is ohms. The current decreases as resistance increases. On the other hand, the current increases as the resistance decreases. A conductor's electrical resistance is affected by the following parameters: The conductor's cross-sectional area, the conductor's length, the conductor's material and the conducting material's temperature. Electrical resistance is inversely proportional to the cross-sectional area and directly proportional to the conductor's length.
Note: The rate of electrical energy transfer over an electric circuit per unit of time is measured as electric power. The S.I. unit of power is watt or joule per second. The quantity of electric power is scalar.
Formula used:
For maximum power, the equivalent resistance should be equal to internal resistance. That is,
$r = {R_E}$
Where ${R_E}$ = equivalent resistant and r = internal resistance.
Equivalent resistance for a series resistance circuit:
${R_E} = {R_1} + {R_2} + {R_3}$
Where ${R_E}$= equivalent resistance and ${R_1},{R_2},{R_3}$ = component resistance.
Equivalent resistance for a parallel resistance circuit:
$\dfrac{1}{{{R_E}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}} + \dfrac{1}{{{R_3}}}$
Where ${R_E}$= equivalent resistance and ${R_1},{R_2},{R_3}$ = component resistance.
Complete step by step solution:
In the triangle part of the circuit, the three sides have two resistances in a series connection. Their equivalent resistance will be ${R_E} = R + R = 2R$. The circuit diagram will be
The equivalent resistance for the three parallel combinations in the circuit will become,
$\dfrac{1}{{{R_E}}} = \dfrac{1}{R} + \dfrac{1}{{2R}} = \dfrac{3}{{2R}} \\
\Rightarrow {R_E} = \dfrac{{2R}}{3}$
The equivalent resistance for the three-series connection is,
${R_E} = \dfrac{{2R}}{3} + \dfrac{{2R}}{3} = \dfrac{{4R}}{3}$
The equivalent resistance for the final parallel connection is,
${R_E} = \dfrac{{\dfrac{{2R}}{3} \times \dfrac{{4R}}{3}}}{{\dfrac{{2R}}{3} + \dfrac{{4R}}{3}}} = \dfrac{{4R}}{9}$
Hence, the correct option is option B.
Additional Information: Resistance blocks the flow of current. The S.I. unit of resistance is ohms. The current decreases as resistance increases. On the other hand, the current increases as the resistance decreases. A conductor's electrical resistance is affected by the following parameters: The conductor's cross-sectional area, the conductor's length, the conductor's material and the conducting material's temperature. Electrical resistance is inversely proportional to the cross-sectional area and directly proportional to the conductor's length.
Note: The rate of electrical energy transfer over an electric circuit per unit of time is measured as electric power. The S.I. unit of power is watt or joule per second. The quantity of electric power is scalar.
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