![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
If equation of sound wave is $y = 0.0015\sin (62.4x + 316t)$ , then its wavelength will be
(A) 2 unit
(B) 0.3unit
(C) 0.1unit
(D) 0.2 unit
Answer
123.9k+ views
Hint: The given equation takes the exact form of the progressive wave equation$y = A\sin (\omega t - kx)$. So, on comparing both the wave functions, find out the value of the propagation constant k. k is related to the wavelength by $k = \dfrac{{2\pi }}{\lambda }$ . Now on substituting the values calculate the wavelength of the wave.
Complete step-by-step answer
A mathematical description of the disturbance created by a wave is called a wave function.
![](https://www.vedantu.com/question-sets/2b15e882-4633-42ba-842b-d00c5f15895b3441782252251227816.png)
We know that, a progressive wave function is given by,
$y = A\sin (\omega t - kx)$
Where,
Y is the displacement; A is the amplitude; \[\omega \]is the angular frequency; x is the position; k is the propagation constant and t is the time.
$y = 0.0015\sin (62.4x + 316t)$
The given equation is similar to this wave function and therefore has corresponding values. On comparing with the progressive wave function we find out the value of the propagation constant also known as angular wave number.
$k = 62.8$
The number of wavelengths in the distance\[2\pi \]is called the wave number which is given by,
$k = \dfrac{{2\pi }}{\lambda }$
Substitute the value of the angular wave number.
$\lambda = \dfrac{{2 \times 3.14}}{{62.8}}$
$\lambda = 0.1unit$
Hence, the wavelength of the wave is 0.1 units and the correct option is C.
Note: If during the propagation of a progressive wave, the particles of the medium perform SHM about their mean position then the wave is known as a harmonic progressive wave. Various forms of progressive wave function.
$y = A\sin 2\pi \left( {\dfrac{t}{T} - \dfrac{x}{\lambda }} \right)$
$y = A\sin \dfrac{{2\pi }}{T}\left( {t - \dfrac{{xT}}{\lambda }} \right)$
$y = A\sin \dfrac{{2\pi }}{\lambda }\left( {vt - x} \right)$
$y = A\sin \omega \left( {t - \dfrac{x}{v}} \right)$
We can also write it in exponential form
$y = A\dfrac{{{e^{i\omega \left( {t - \dfrac{x}{v}} \right)}} - {e^{ - i\omega \left( {t - \dfrac{x}{v}} \right)}}}}{{2i}}$
Complete step-by-step answer
A mathematical description of the disturbance created by a wave is called a wave function.
![](https://www.vedantu.com/question-sets/2b15e882-4633-42ba-842b-d00c5f15895b3441782252251227816.png)
We know that, a progressive wave function is given by,
$y = A\sin (\omega t - kx)$
Where,
Y is the displacement; A is the amplitude; \[\omega \]is the angular frequency; x is the position; k is the propagation constant and t is the time.
$y = 0.0015\sin (62.4x + 316t)$
The given equation is similar to this wave function and therefore has corresponding values. On comparing with the progressive wave function we find out the value of the propagation constant also known as angular wave number.
$k = 62.8$
The number of wavelengths in the distance\[2\pi \]is called the wave number which is given by,
$k = \dfrac{{2\pi }}{\lambda }$
Substitute the value of the angular wave number.
$\lambda = \dfrac{{2 \times 3.14}}{{62.8}}$
$\lambda = 0.1unit$
Hence, the wavelength of the wave is 0.1 units and the correct option is C.
Note: If during the propagation of a progressive wave, the particles of the medium perform SHM about their mean position then the wave is known as a harmonic progressive wave. Various forms of progressive wave function.
$y = A\sin 2\pi \left( {\dfrac{t}{T} - \dfrac{x}{\lambda }} \right)$
$y = A\sin \dfrac{{2\pi }}{T}\left( {t - \dfrac{{xT}}{\lambda }} \right)$
$y = A\sin \dfrac{{2\pi }}{\lambda }\left( {vt - x} \right)$
$y = A\sin \omega \left( {t - \dfrac{x}{v}} \right)$
We can also write it in exponential form
$y = A\dfrac{{{e^{i\omega \left( {t - \dfrac{x}{v}} \right)}} - {e^{ - i\omega \left( {t - \dfrac{x}{v}} \right)}}}}{{2i}}$
Recently Updated Pages
Difference Between Circuit Switching and Packet Switching
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Mass and Weight
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Participating Colleges 2024 - A Complete List of Top Colleges
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Sign up for JEE Main 2025 Live Classes - Vedantu
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2025 Helpline Numbers - Center Contact, Phone Number, Address
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Login 2045: Step-by-Step Instructions and Details
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Units and Measurements Class 11 Notes: CBSE Physics Chapter 1
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
![arrow-right](/cdn/images/seo-templates/arrow-right.png)