
If the current is flowing through a 10 ohm resistor, then indicate in which case the maximum heat will be generated?
(A) 5 ampere in 2 minutes
(B) 4 ampere in 3 minutes
(C) 3 ampere in 6 minutes
(D) 2 ampere in 5 minutes
Answer
131.7k+ views
Hint: Heat generated is related to the energy consumed by the resistor. The energy consumed is directly proportional to the square of the electric current. Check which of the options will consume the most energy.
Formula used: In this solution we will be using the following formulae;
\[H = {I^2}Rt\] where \[H\] is the heat generated by the resistor, \[I\] is the amount of current flowing through the resistor, \[R\] is the resistance of the resistor and \[t\] is the time for which the current flowed through the resistor.
Complete Step-by-Step solution:
The heat generated is simply the electrical energy consumed by the resistor.
Hence, to solve the above question, we calculate the energy consumed in each case of the options one after the other then check for which of them is maximum.
Hence the heat generated can be given as
\[H = {I^2}Rt\] where \[H\] is the heat generated by the resistor, \[I\] is the amount of current flowing through the resistor, \[R\] is the resistance of the resistor and \[t\] is the time for which the current flowed through the resistor.
Option A, current 5 ampere in 2 minutes
\[{H_a} = {5^2}\left( {10} \right)2 = 500J\]
For option B,
\[{H_b} = {4^2}\left( {10} \right)3 = 480J\]
For option C,
\[{H_c} = {3^2}\left( {10} \right)6 = 540J\]
And for option D,
\[{H_d} = {2^2}\left( {10} \right)5 = 200J\]
As can be observed, the maximum heat generated is option C.
Hence, the correct option is option C
Note: Alternatively, since the resistor is the same in all cases, we can simply find the heat generated per unit ohms in each case. As in
For option A,
\[{h_a} = {5^2} \times 2 = 50J/\Omega \] where \[h\] is the heat generated per unit resistance.
For option B,
\[{h_b} = {4^2} \times 3 = 48J/\Omega \]
For option C,
\[{h_d} = {3^2} \times 6 = 54J/\Omega \]
And for option D
\[{h_d} = {2^2} \times 5 = 20J/\Omega \]
And this still shows that option C is the correct option.
Formula used: In this solution we will be using the following formulae;
\[H = {I^2}Rt\] where \[H\] is the heat generated by the resistor, \[I\] is the amount of current flowing through the resistor, \[R\] is the resistance of the resistor and \[t\] is the time for which the current flowed through the resistor.
Complete Step-by-Step solution:
The heat generated is simply the electrical energy consumed by the resistor.
Hence, to solve the above question, we calculate the energy consumed in each case of the options one after the other then check for which of them is maximum.
Hence the heat generated can be given as
\[H = {I^2}Rt\] where \[H\] is the heat generated by the resistor, \[I\] is the amount of current flowing through the resistor, \[R\] is the resistance of the resistor and \[t\] is the time for which the current flowed through the resistor.
Option A, current 5 ampere in 2 minutes
\[{H_a} = {5^2}\left( {10} \right)2 = 500J\]
For option B,
\[{H_b} = {4^2}\left( {10} \right)3 = 480J\]
For option C,
\[{H_c} = {3^2}\left( {10} \right)6 = 540J\]
And for option D,
\[{H_d} = {2^2}\left( {10} \right)5 = 200J\]
As can be observed, the maximum heat generated is option C.
Hence, the correct option is option C
Note: Alternatively, since the resistor is the same in all cases, we can simply find the heat generated per unit ohms in each case. As in
For option A,
\[{h_a} = {5^2} \times 2 = 50J/\Omega \] where \[h\] is the heat generated per unit resistance.
For option B,
\[{h_b} = {4^2} \times 3 = 48J/\Omega \]
For option C,
\[{h_d} = {3^2} \times 6 = 54J/\Omega \]
And for option D
\[{h_d} = {2^2} \times 5 = 20J/\Omega \]
And this still shows that option C is the correct option.
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

Difference Between Circuit Switching and Packet Switching

Difference Between Mass and Weight

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
Degree of Dissociation and Its Formula With Solved Example for JEE

Displacement-Time Graph and Velocity-Time Graph for JEE

Clemmenson and Wolff Kishner Reductions for JEE

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

In Bohrs model of the hydrogen atom the radius of the class 12 physics JEE_Main

JEE Main 2025 Session 2 Registration Open – Apply Now! Form Link, Last Date and Fees

Other Pages
JEE Advanced 2024 Syllabus Weightage

CBSE Date Sheet 2025 Class 12 - Download Timetable PDF for FREE Now

JEE Main 2025 - Session 2 Registration Open | Exam Dates, Answer Key, PDF

CBSE Class 10 Hindi Sample Papers with Solutions 2024-25 FREE PDF

CBSE Board Exam Date Sheet Class 10 2025 (OUT): Download Exam Dates PDF

CBSE Class 10 Hindi Course-B Syllabus 2024-25 - Revised PDF Download
