
If the intensity of sound is increased by a factor of \[30\], by how many decibels is the sound level increased?
A) \[12dB\]
B) \[14.77dB\]
C) \[10dB\]
D) \[13dB\]
Answer
232.8k+ views
Hint: Sound Intensity, also known as acoustic intensity, is the power the sound wave carries per unit area in a direction perpendicular to the aforementioned area. Decibel, on the other hand, is a logarithmic unit, used to measure sound level.
Formula used: \[\beta =10\log \dfrac{I}{{{I}_{0}}}\]
Complete step by step solution:
We have been given that intensity of sound increases by a factor of \[30\]
One decibel is equal to ten times the logarithm to base \[10\] (or common logarithm) of the power or the intensity ratio. It can be more clearly expressed as a formula,
\[\beta =10\log \dfrac{I}{{{I}_{0}}}\] where \[\beta \] is the sound level in decibels, \[I\] is the intensity of sound and \[{{I}_{0}}\] is the threshold intensity of sound.
Let the initial intensity of the sound be \[I\], we can express it in decibels as \[{{\beta }_{1}}=10\log \dfrac{I}{{{I}_{0}}}\]
Now, the intensity of sound is increased by a factor of \[30\], so the new intensity of the sound will be \[30I\]. The loudness of this intensity can be expressed as \[{{\beta }_{2}}=10\log \dfrac{30I}{{{I}_{0}}}\]
Since we are concerned with the increase in the loudness, we can find it by taking the difference between the two calculated decibel loudness,
Increase in sound level \[\Rightarrow {{\beta }_{2}}-{{\beta }_{1}}\]
\[{{\beta }_{2}}-{{\beta }_{1}}=10\log \dfrac{30I}{{{I}_{0}}}-10\log \dfrac{I}{{{I}_{0}}}\]
Using properties of logarithms, we can now say that
\[\begin{align}
& {{\beta }_{2}}-{{\beta }_{1}}=10(\log \dfrac{30(\dfrac{I}{{{I}_{0}}})}{1(\dfrac{I}{{{I}_{0}}})}) \\
& \Rightarrow {{\beta }_{2}}-{{\beta }_{1}}=10\log 30=14.77dB \\
\end{align}\]
Hence, there is an increase of \[14.77dB\] in the sound level when intensity increases by a factor of \[30\].
Note:Loudness refers to how loud or soft a sound seems to a listener. The loudness of sound is determined by its intensity and intensity, in turn, is determined by the amplitude of the sound waves and the distance travelled by the sound waves from the source.
Formula used: \[\beta =10\log \dfrac{I}{{{I}_{0}}}\]
Complete step by step solution:
We have been given that intensity of sound increases by a factor of \[30\]
One decibel is equal to ten times the logarithm to base \[10\] (or common logarithm) of the power or the intensity ratio. It can be more clearly expressed as a formula,
\[\beta =10\log \dfrac{I}{{{I}_{0}}}\] where \[\beta \] is the sound level in decibels, \[I\] is the intensity of sound and \[{{I}_{0}}\] is the threshold intensity of sound.
Let the initial intensity of the sound be \[I\], we can express it in decibels as \[{{\beta }_{1}}=10\log \dfrac{I}{{{I}_{0}}}\]
Now, the intensity of sound is increased by a factor of \[30\], so the new intensity of the sound will be \[30I\]. The loudness of this intensity can be expressed as \[{{\beta }_{2}}=10\log \dfrac{30I}{{{I}_{0}}}\]
Since we are concerned with the increase in the loudness, we can find it by taking the difference between the two calculated decibel loudness,
Increase in sound level \[\Rightarrow {{\beta }_{2}}-{{\beta }_{1}}\]
\[{{\beta }_{2}}-{{\beta }_{1}}=10\log \dfrac{30I}{{{I}_{0}}}-10\log \dfrac{I}{{{I}_{0}}}\]
Using properties of logarithms, we can now say that
\[\begin{align}
& {{\beta }_{2}}-{{\beta }_{1}}=10(\log \dfrac{30(\dfrac{I}{{{I}_{0}}})}{1(\dfrac{I}{{{I}_{0}}})}) \\
& \Rightarrow {{\beta }_{2}}-{{\beta }_{1}}=10\log 30=14.77dB \\
\end{align}\]
Hence, there is an increase of \[14.77dB\] in the sound level when intensity increases by a factor of \[30\].
Note:Loudness refers to how loud or soft a sound seems to a listener. The loudness of sound is determined by its intensity and intensity, in turn, is determined by the amplitude of the sound waves and the distance travelled by the sound waves from the source.
Recently Updated Pages
Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

