
In a superheterodyne receiver, the IF is \[455{\text{ }}kHz\] . If it is tuned \[1200{\text{ }}kHz\] , the image frequency will be
A) \[1562{\text{ }}kHz\]
B) \[1675{\text{ }}kHz\]
C) \[2110{\text{ }}kHz\]
D) \[2025{\text{ }}kHz\]
Answer
131.7k+ views
Hint:In a superheterodyne receiver, the station frequency plus we have to do twice the intermediate frequency equal to an image frequency is an undesired input frequency.
Complete step by step answer:
It is given that the question as \[455{\text{ }}kHz\] is called the intermediate frequency (IF) of a radio.
Without going into great detail, \[455{\text{ }}kHz\] is one of the most commonly used IFs used in the super heterodyne radio.
In a superheterodyne receiver,
IF = \[455{\text{ }}kHz\]
It is tuned to\[{\text{1200 }}kHz\]
To find the image frequency is
Any signal is capable of interfering with super heterodyne receiver if,
Image frequency = tuned signal$ \pm 2 \times I.F$
Tuned frequency = \[{\text{1200 }}kHz\] and
IF =\[455{\text{ }}kHz\] is given.
Therefore, image frequency $ = 1200 \pm 910$
Hence, the image frequency is = \[{\text{2110 }}kHz\] or \[{\text{290 }}kHz\].
So, the image frequency will be option (C) is \[{\text{2110 }}kHz\].
Additional Information:Heterodyning which simply means mixing, superheterodyne receiver works on the principle.
By a local oscillator it is a type of receiver which mixes the received signal frequency with the frequency of the signal generated.
As a known intermediate frequency the output of the mixer provides a lower fixed frequency.
The sum and their difference of the applied frequencies and also their harmonics that can in multiple frequencies applied that is a nonlinear device to produce the new frequencies.
Note: The most suitable type for the great majority of radio receiver applications; the advantages of the super heterodyne receiver make it.
AM, FM, communications, Single-sideband,
Television and even radar receivers all use it,
With only slight modifications in Super heterodyne Principle.
Complete step by step answer:
It is given that the question as \[455{\text{ }}kHz\] is called the intermediate frequency (IF) of a radio.
Without going into great detail, \[455{\text{ }}kHz\] is one of the most commonly used IFs used in the super heterodyne radio.
In a superheterodyne receiver,
IF = \[455{\text{ }}kHz\]
It is tuned to\[{\text{1200 }}kHz\]
To find the image frequency is
Any signal is capable of interfering with super heterodyne receiver if,
Image frequency = tuned signal$ \pm 2 \times I.F$
Tuned frequency = \[{\text{1200 }}kHz\] and
IF =\[455{\text{ }}kHz\] is given.
Therefore, image frequency $ = 1200 \pm 910$
Hence, the image frequency is = \[{\text{2110 }}kHz\] or \[{\text{290 }}kHz\].
So, the image frequency will be option (C) is \[{\text{2110 }}kHz\].
Additional Information:Heterodyning which simply means mixing, superheterodyne receiver works on the principle.
By a local oscillator it is a type of receiver which mixes the received signal frequency with the frequency of the signal generated.
As a known intermediate frequency the output of the mixer provides a lower fixed frequency.
The sum and their difference of the applied frequencies and also their harmonics that can in multiple frequencies applied that is a nonlinear device to produce the new frequencies.
Note: The most suitable type for the great majority of radio receiver applications; the advantages of the super heterodyne receiver make it.
AM, FM, communications, Single-sideband,
Television and even radar receivers all use it,
With only slight modifications in Super heterodyne Principle.
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

Difference Between Circuit Switching and Packet Switching

Difference Between Mass and Weight

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
Degree of Dissociation and Its Formula With Solved Example for JEE

Displacement-Time Graph and Velocity-Time Graph for JEE

Clemmenson and Wolff Kishner Reductions for JEE

Sir C V Raman won the Nobel Prize in which year A 1928 class 12 physics JEE_Main

In Bohrs model of the hydrogen atom the radius of the class 12 physics JEE_Main

JEE Main 2025 Session 2 Registration Open – Apply Now! Form Link, Last Date and Fees

Other Pages
JEE Advanced 2024 Syllabus Weightage

CBSE Date Sheet 2025 Class 12 - Download Timetable PDF for FREE Now

JEE Main 2025 - Session 2 Registration Open | Exam Dates, Answer Key, PDF

CBSE Class 10 Hindi Sample Papers with Solutions 2024-25 FREE PDF

CBSE Board Exam Date Sheet Class 10 2025 (OUT): Download Exam Dates PDF

CBSE Class 10 Hindi Course-B Syllabus 2024-25 - Revised PDF Download
