Answer
Verified
108.9k+ views
Hint: Intrinsic semiconductor is a type of semiconductor which is in pure state and when it is doped with some impurities, it changes into extrinsic semiconductor. In a doped semiconductor, ${n_i}^2 = {n_e}{n_h}$ where ${n_e}$ and ${n_h}$ are the no. density of electrons and holes respectively and ${n_i}$is the no. density of charge carries i.e. electrons or holes in the intrinsic semiconductor.
Complete step by step answer:
We should know that the semiconductors are basically of two types Intrinsic and Extrinsic. Intrinsic semiconductor is a type of semiconductor which is in pure state and when it is doped with some impurities, it changes into extrinsic semiconductor. So, according to the question, indium is that impurity which doped in intrinsic semiconductor.
As in a doped semiconductor, ${n_i}^2 = {n_e}{n_h}$ where ${n_e}$ and ${n_h}$ are the no. density of electrons and holes respectively and ${n_i}$is the no. density of charge carries i.e. electrons or holes in the intrinsic semiconductor.
So, according to the question the no. density of electrons of intrinsic semiconductor is given ${n_i} = 7.07 \times {10^{15}}{m^{ - 3}}$ and no. density of holes when it is doped is given ${n_h} = 5 \times {10^{22}}{m^{ - 3}}$ .
So, substituting these values in the equation we have
${\left( {7.07 \times {{10}^{15}}} \right)^2} = {n_i} \times \left( {5 \times {{10}^{22}}} \right)$
On solving this we have the no. density of conduction electrons as
${n_i} = 0.99 \times {10^9} \approx 1 \times {10^9}{m^{ - 3}}$
Hence, option B is correct.
Note: The doping in the intrinsic semiconductor is done to improve its functionality and this is done in two different ways. When it is doped with the elements like As, Sb, Bi etc. in which electrons is in majority is known as n-type semiconductor whereas when is doped with the elements like Al, B, In etc. in which holes comes in majority is known as p-type semiconductor.
Complete step by step answer:
We should know that the semiconductors are basically of two types Intrinsic and Extrinsic. Intrinsic semiconductor is a type of semiconductor which is in pure state and when it is doped with some impurities, it changes into extrinsic semiconductor. So, according to the question, indium is that impurity which doped in intrinsic semiconductor.
As in a doped semiconductor, ${n_i}^2 = {n_e}{n_h}$ where ${n_e}$ and ${n_h}$ are the no. density of electrons and holes respectively and ${n_i}$is the no. density of charge carries i.e. electrons or holes in the intrinsic semiconductor.
So, according to the question the no. density of electrons of intrinsic semiconductor is given ${n_i} = 7.07 \times {10^{15}}{m^{ - 3}}$ and no. density of holes when it is doped is given ${n_h} = 5 \times {10^{22}}{m^{ - 3}}$ .
So, substituting these values in the equation we have
${\left( {7.07 \times {{10}^{15}}} \right)^2} = {n_i} \times \left( {5 \times {{10}^{22}}} \right)$
On solving this we have the no. density of conduction electrons as
${n_i} = 0.99 \times {10^9} \approx 1 \times {10^9}{m^{ - 3}}$
Hence, option B is correct.
Note: The doping in the intrinsic semiconductor is done to improve its functionality and this is done in two different ways. When it is doped with the elements like As, Sb, Bi etc. in which electrons is in majority is known as n-type semiconductor whereas when is doped with the elements like Al, B, In etc. in which holes comes in majority is known as p-type semiconductor.
Recently Updated Pages
If x2 hx 21 0x2 3hx + 35 0h 0 has a common root then class 10 maths JEE_Main
The radius of a sector is 12 cm and the angle is 120circ class 10 maths JEE_Main
For what value of x function fleft x right x4 4x3 + class 10 maths JEE_Main
What is the area under the curve yx+x1 betweenx0 and class 10 maths JEE_Main
The volume of a sphere is dfrac43pi r3 cubic units class 10 maths JEE_Main
Which of the following is a good conductor of electricity class 10 chemistry JEE_Main