![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
In the following V-T diagram what is the relation between \[{P_1}\] and \[{P_2}\]:
![](https://www.vedantu.com/question-sets/1c55c681-dc3c-4864-85a6-02b5191639b7677149870862053713.png)
A) ${{\text{P}}_2} = {{\text{P}}_1}$
B) ${{\text{P}}_2} > {{\text{P}}_1}$
C) ${{\text{P}}_2} < {{\text{P}}_1}$
D) Cannot be predicted
Answer
124.5k+ views
Hint:
i)Ideal gas equation: It is the relationship between Boyle’s law, Charles law, and Avogadro’s law.
ii) Boyle’s law: This describes how the pressure of a gas tends to change as the volume of the container.
iii) Charles law: This describes how gas tends to expand when heated.
iv) Avogadro’s law: This describes the relationship between the volumes of gas to the amount of substance of gas present.
Formula used:
Ideal gas equation,${\text{PV = RT}}$,
Here\[\;P = \] pressure of the gas,
\[V = \] volume of the gas,
\[T = \] temperature,
\[R = \] universal gas constant
Complete step by step solution:
It is given that \[{P_1}\]and \[{P_2}\] is the pressure from the graph.
Therefore, the ideal gas equation can be re-written as, $\dfrac{{\text{V}}}{{\text{T}}} = \dfrac{{\text{R}}}{{\text{P}}}$
From the given graph we see that the slope of \[2\,\] is greater than the slope of\[1\].
Therefore, we can write that, $\dfrac{{{{\text{V}}_2}}}{{{{\text{T}}_2}}} > \dfrac{{{{\text{V}}_1}}}{{{{\text{T}}_1}}}$
From the ideal gas equation, $\dfrac{1}{{{{\text{P}}_2}}} > \dfrac{1}{{{{\text{P}}_1}}}$
So we can write it as,
$ \Rightarrow {{\text{P}}_2} < {{\text{P}}_1}$
Hence the correct option is (C).
Note:
i) By using the ideal gas equation, we can measure the temperature accurately irrespective of their masses and other physical quantities.
ii) Boyle’s law in thermodynamics explains the volume of a gas is inversely proportional to its pressure exerted by a gas at a constant temperature.
iii) Charles law in thermodynamics defines where the volume of a fixed mass of a dry gas is directly proportional to its absolute temperature.
iv) Avogadro’s law in thermodynamics where number of atoms/ molecules of a gas is directly proportional to the volume occupied by the gas at a constant temperature.
v) Calorimeter is a device used to measure the heat energy added to the system
i)Ideal gas equation: It is the relationship between Boyle’s law, Charles law, and Avogadro’s law.
ii) Boyle’s law: This describes how the pressure of a gas tends to change as the volume of the container.
iii) Charles law: This describes how gas tends to expand when heated.
iv) Avogadro’s law: This describes the relationship between the volumes of gas to the amount of substance of gas present.
Formula used:
Ideal gas equation,${\text{PV = RT}}$,
Here\[\;P = \] pressure of the gas,
\[V = \] volume of the gas,
\[T = \] temperature,
\[R = \] universal gas constant
Complete step by step solution:
It is given that \[{P_1}\]and \[{P_2}\] is the pressure from the graph.
Therefore, the ideal gas equation can be re-written as, $\dfrac{{\text{V}}}{{\text{T}}} = \dfrac{{\text{R}}}{{\text{P}}}$
From the given graph we see that the slope of \[2\,\] is greater than the slope of\[1\].
Therefore, we can write that, $\dfrac{{{{\text{V}}_2}}}{{{{\text{T}}_2}}} > \dfrac{{{{\text{V}}_1}}}{{{{\text{T}}_1}}}$
From the ideal gas equation, $\dfrac{1}{{{{\text{P}}_2}}} > \dfrac{1}{{{{\text{P}}_1}}}$
So we can write it as,
$ \Rightarrow {{\text{P}}_2} < {{\text{P}}_1}$
Hence the correct option is (C).
Note:
i) By using the ideal gas equation, we can measure the temperature accurately irrespective of their masses and other physical quantities.
ii) Boyle’s law in thermodynamics explains the volume of a gas is inversely proportional to its pressure exerted by a gas at a constant temperature.
iii) Charles law in thermodynamics defines where the volume of a fixed mass of a dry gas is directly proportional to its absolute temperature.
iv) Avogadro’s law in thermodynamics where number of atoms/ molecules of a gas is directly proportional to the volume occupied by the gas at a constant temperature.
v) Calorimeter is a device used to measure the heat energy added to the system
Recently Updated Pages
Difference Between Circuit Switching and Packet Switching
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Mass and Weight
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Participating Colleges 2024 - A Complete List of Top Colleges
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Sign up for JEE Main 2025 Live Classes - Vedantu
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2025 Helpline Numbers - Center Contact, Phone Number, Address
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Class 11 JEE Main Physics Mock Test 2025
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Units and Measurements Class 11 Notes: CBSE Physics Chapter 1
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
![arrow-right](/cdn/images/seo-templates/arrow-right.png)