One coulomb charge is equivalent to the charge contained in:
A) \[26 \times {10^{19}}\,\,electrons\]
B) \[2.65 \times {10^{18}}\,\,electrons\]
C) \[6.2 \times {10^{19\,}}electrons\]
D) \[6.25 \times {10^{18}}\,elctrons\]
Answer
Verified
122.7k+ views
Hint: As we know \[Q\] coulomb (\[C\]) charge contains\[n\]times the charge of electron, electrons, and can be expressed as \[Q = ne\], where \[e\]is the charge of electron and\[n\]is the number of electron. Here, we have to find the number of electron contained in \[1\,C\]
Complete step by step answer:
As we know \[Q\] coulomb (\[C\]) charge contains n times the charge of electron, electrons, and can be expressed as \[Q = ne\], where \[e\]is the charge of electron (\[i.e.\] \[1.6 \times {10^{ - 19}}C\])
Now, according we have to find the number of electrons in 1 coulomb charge
\[ \Rightarrow \]\[Q = ne\]
On putting the values of \[Q\]and \[e\]we get,
\[ \Rightarrow \]\[1 = n \times 1.6 \times {10^{ - 19}}\]
\[ \Rightarrow \]\[n = 6.25 \times {10^{18}}\]
Hence, the number of electrons contained in \[1\,C\]charge is \[6.25 \times {10^{18}}\] that is option (D)
Additional information:
A coulomb is an enormous charge – two \[1\,C\]charges that are \[1\,\,m\] apart exert a force of \[9 \times {10^9}Newton(N)\]. That's over two million tonnes, 720 times as much as the thrust of a space shuttle solid rocket booster during lift-off.
Note: As we can see here that this is a complete formula based question. For solving this type of questions we should memorize the basic concepts and their important formulas. Here we had to find the number of electrons which we have find with the formula
Complete step by step answer:
As we know \[Q\] coulomb (\[C\]) charge contains n times the charge of electron, electrons, and can be expressed as \[Q = ne\], where \[e\]is the charge of electron (\[i.e.\] \[1.6 \times {10^{ - 19}}C\])
Now, according we have to find the number of electrons in 1 coulomb charge
\[ \Rightarrow \]\[Q = ne\]
On putting the values of \[Q\]and \[e\]we get,
\[ \Rightarrow \]\[1 = n \times 1.6 \times {10^{ - 19}}\]
\[ \Rightarrow \]\[n = 6.25 \times {10^{18}}\]
Hence, the number of electrons contained in \[1\,C\]charge is \[6.25 \times {10^{18}}\] that is option (D)
Additional information:
A coulomb is an enormous charge – two \[1\,C\]charges that are \[1\,\,m\] apart exert a force of \[9 \times {10^9}Newton(N)\]. That's over two million tonnes, 720 times as much as the thrust of a space shuttle solid rocket booster during lift-off.
Note: As we can see here that this is a complete formula based question. For solving this type of questions we should memorize the basic concepts and their important formulas. Here we had to find the number of electrons which we have find with the formula
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Concept of CP and CV of Gas - Important Concepts and Tips for JEE
Trending doubts
JEE Mains 2025: Check Important Dates, Syllabus, Exam Pattern, Fee and Updates
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Chemistry Question Paper with Answer Keys and Solutions
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
JEE Main Chemistry Exam Pattern 2025
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11
Electric field due to uniformly charged sphere class 12 physics JEE_Main