
One light-year is defined as the distance travelled by light in one year. The speed of light is $3 \times {10^8}\,m/s$. The same in the meter is?
(A) $3 \times {10^{12}}m$
(B) $9.461 \times {10^{15}}m$
(C) $3 \times {10^{15}}m$
(D) None of these
Answer
233.1k+ views
Hint: A light-year is a unit of distance denoted by the symbol ‘ly’. It is used to measure the distance between two astronomical objects.
Formula used: In this solution, we will use the following formula
\[v = \dfrac{d}{t}\] where $v$ is the velocity of the light, $d$ is the distance it travels in time $t$
Complete step by step answer:
As mentioned in the question, one light-year is defined as the distance travelled by light in one year. We’ve also been given that the speed of light is $3 \times {10^8}\,m/s$. Since the relation between the velocity, distance, and time is given as:
\[v = \dfrac{d}{t}\]
\[ \Rightarrow d = vt\]
Hence the distance travelled by light in one year will be the product of the velocity of light and the time it travels for. We’ve been given light ray travels for one year.
Now we know that in one year the number of seconds will be
\[t = 365\,\,{\text{days}}\,\, \times \,24\,{\text{hours}}\, \times \,60\,\min {\text{s}}\, \times \,60\,\sec \]
\[ \Rightarrow t = 31536000\,\sec \]
Now that we know the time, the light travels for, we can substitute $v = 3 \times {10^8}\,m/s$ in the formula for velocity and get
$d = 3 \times {10^8} \times 31536000$
$ \Rightarrow d = 9.46\, \times \,{10^{15}}\,m$
Hence the distance covered by light in one year is $9.46\, \times \,{10^{15}}\,m$. This is a very large distance as compared to the radius of the Earth which is 6400 km so a light-year is only used to measure large distances.
Hence the correct answer is option B.
Note: The distance travelled by light in a given amount of time is the largest compared to any other travelling object hence the term light-year is used as a unit for measuring large distances. The speed of light mentioned in the question is only in a vacuum while in different mediums, light can have lower speeds.
Formula used: In this solution, we will use the following formula
\[v = \dfrac{d}{t}\] where $v$ is the velocity of the light, $d$ is the distance it travels in time $t$
Complete step by step answer:
As mentioned in the question, one light-year is defined as the distance travelled by light in one year. We’ve also been given that the speed of light is $3 \times {10^8}\,m/s$. Since the relation between the velocity, distance, and time is given as:
\[v = \dfrac{d}{t}\]
\[ \Rightarrow d = vt\]
Hence the distance travelled by light in one year will be the product of the velocity of light and the time it travels for. We’ve been given light ray travels for one year.
Now we know that in one year the number of seconds will be
\[t = 365\,\,{\text{days}}\,\, \times \,24\,{\text{hours}}\, \times \,60\,\min {\text{s}}\, \times \,60\,\sec \]
\[ \Rightarrow t = 31536000\,\sec \]
Now that we know the time, the light travels for, we can substitute $v = 3 \times {10^8}\,m/s$ in the formula for velocity and get
$d = 3 \times {10^8} \times 31536000$
$ \Rightarrow d = 9.46\, \times \,{10^{15}}\,m$
Hence the distance covered by light in one year is $9.46\, \times \,{10^{15}}\,m$. This is a very large distance as compared to the radius of the Earth which is 6400 km so a light-year is only used to measure large distances.
Hence the correct answer is option B.
Note: The distance travelled by light in a given amount of time is the largest compared to any other travelling object hence the term light-year is used as a unit for measuring large distances. The speed of light mentioned in the question is only in a vacuum while in different mediums, light can have lower speeds.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

