Question

$\text{RCOOR'}$ can be prepared by:
(a) Esterification of RCOOH
(b) Esterification of $(RCO{)}_{2}O$
(c) Baeyer - Villiger oxidation of $\text{RCOR'}$ with peroxy acid
(d) Reaction of RCOCl with $\text{R'OH}$

Answer 1

Hint: In order to answer the question, we have to have knowledge about the structure of carboxylic acid. Esterification process can be explained in an easier manner then.

Complete step-by-step answer:
On esterification of carboxylic acid (RCOOH), or an acid anhydride (RCOOCOR) with an alcohol ($\text{R'OH}$), an ester ($\text{RCOOR'}$) is formed. This reaction can be backed by the following chemical equation.
$\text{RCOOH + {R}'OH }\stackrel{}{\leftrightarrows }\text{ RCOO{R}' + }{\text{H}}_{\text{2}}\text{O}\}\text{Esterification of Carboxylic Acid with Alcohol}$
$$\text{RCOOCOR + {R}'OH }\stackrel{}{\leftrightarrows }\text{ RCOO{R}' + RCOOH}\}\text{Esterification of Acid Anhydrides with Alcohol}$$
An example of the same is shown by the following chemical equation.
$$\begin{array}{rl}& \text{ C}{\text{H}}_{\text{3}}\text{COOH + }{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH }\stackrel{}{\leftrightarrows }\text{ C}{\text{H}}_{\text{3}}\text{COO}{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{ + }{\text{H}}_2\text{O}\\ & \text{ Acid Chloride Alcohol Ester Water}\end{array}$$

$$\begin{array}{rl}& {\left(\text{C}{\text{H}}_{\text{3}}\text{CO}\right)}_{\text{2}}\text{O + }{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH }\stackrel{}{\leftrightarrows }\text{ C}{\text{H}}_{\text{3}}\text{COO}{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{ + C}{\text{H}}_{\text{3}}\text{COOH}\\ & \text{Acid Anhydrade Alcohol Ester Carboxylic Acid}\end{array}$$
An ester ($\text{RCOOR'}$) is obtained when a ketone ($\text{RCOR'}$) is treated with peroxy acid ($\text{R''COOOR}$), also known as the Baeyer Villiger oxidation. This reaction can be backed by the following chemical equation.
$\text{RCO{R}' + {R}''COOOH }\stackrel{-\text{{R}''COOH}}{\leftrightarrows }\text{ RCOO{R}' }\}\text{Baeyer Villiger Oxydation}$
An example of the same is shown by the following chemical equation.
$$\begin{array}{rl}& \text{C}{\text{H}}_{\text{3}}\text{CO}{\text{C}}_2{\text{H}}_5\text{ + }{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{COOOH }\stackrel{-{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{COOH}}{\leftrightarrows }\text{ C}{\text{H}}_{\text{3}}\text{COO}{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\\ & \text{ Ketone Peroxy Acid Ester}\end{array}$$

Also an ester ($\text{RCOOR'}$) is formed when an acid chloride (RCOCl) reacts with an alcohol ($\text{R'OH}$). This reaction can be backed by the following chemical equation.
$\text{RCOCl + {R}'OH }\stackrel{}{\leftrightarrows }\text{ RCOO{R}' + HCl}\}\text{Reaction of Acid Chloride with Alcohol}$
An example of the same is shown by the following chemical equation.
  $$\begin{array}{rl}& \text{ C}{\text{H}}_{\text{3}}\text{COCl + }{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH }\stackrel{}{\leftrightarrows }\text{ C}{\text{H}}_{\text{3}}\text{COO}{\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{ + HCl}\\ & \text{ Acid Chloride Alcohol Ester Hydrochloric Acid}\end{array}$$
So we can conclude that $\text{RCOOR'}$can be prepared by:
Esterification of RCOOH
Baeyer - Villiger oxidation of $\text{RCOR'}$ with peroxy acid
Reaction of RCOCl with $\text{R'OH}$
Therefore, the correct options are Option A, Option B, Option C and Option D.

Note: We should be familiar with the concept of esterification. So here is the definition. Esterification is a general name for a chemical reaction in which two reactants, which are typically alcohols and an acid, form an ester as a reaction product. Esters are common in organic chemistry and biological materials and often have a pleasant characteristic fruity odor.
Let us now know the definition of Baeyer - Villiger oxidation. Baeyer - Villiger oxidation is an organic reaction that forms an ester from a ketone or a lactone from acyclic ketones using peroxyacids or peroxides as the oxidant.