Answer
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Hint: In the given question, the circuit has two loops. We can apply Kirchhoff’s law for each loop to get the unknown current, voltage or resistance values by using the values given. We need to find the reading of the ammeter in a loop, so we will use the Kirchhoff’s second (voltage) law. As we know, Kirchhoff’s voltage law states that “The voltage around a loop is equal to the sum of every voltage drop in the same loop for any closed circuit”. We will use this law and form the equations for both loops separately and then we can solve the equations to get the value of the unknown parameter.
Complete step by step solution:
We will show the given circuit and name the different parameters in the diagram as shown below:
From the circuit, there are two loops i.e. ABCDEA and HCDFGH.
Now, to calculate the unknown parameters, we will use Kirchhoff's voltage law for both loops separately. We will calculate each voltage drop in a loop and put it equal to the voltage in the circuit.
For loop ABCDEA,
\[
\Rightarrow 2{i_1} + 2\left( {{i_1} + {i_2}} \right) = 2 \\
\Rightarrow 2{i_1} + 2{i_1} + 2{i_2} = 2 \\
\Rightarrow 4{i_1} + 2{i_2} = 2 \\
\Rightarrow 2{i_1} + 2{i_2} = 1...\left( 1 \right) \\
\]
For loop HCDFGH,
$
\Rightarrow 2\left( {{i_1} + {i_2}} \right) + 2{i_2} = 2 \\
\Rightarrow 2{i_1} + 2{i_2} + 2{i_2} = 2 \\
\Rightarrow 2{i_1} + 4{i_2} = 2 \\
\Rightarrow {i_1} + 2{i_2} = 1...\left( 2 \right) \\
$
From the equation (1) and (2),
$
\Rightarrow {i_1} + 2\left( {1 - 2{i_1}} \right) = 1 \\
\Rightarrow - 3{i_1} = - 1 \\
\Rightarrow {i_1} = \dfrac{1}{3}A \\
$
On solving,
$
\Rightarrow {i_2} = 1 - 2\left( {\dfrac{1}{3}} \right) \\
\Rightarrow {i_2} = \dfrac{1}{3}A \\
$
Thus, we can calculate the ammeter reading by adding the both currents.
$
i = {i_1} + {i_2} \\
\Rightarrow i = \dfrac{1}{3} + \dfrac{1}{3} \\
\Rightarrow i = \dfrac{2}{3}A \\
$
Therefore, the ammeter reading is $\dfrac{2}{3}A$ .
Hence, the correct option is (C).
Note: In the given question, we need to analyse the circuit and find the law which will help us to find the unknown parameter. For any circuit, we have to look for nodes or loops which are given. After that we can apply Kirchhoff's current law if nodes are given or Kirchhoff’s voltage law if loops are given. The equations for voltage drop and node current will lead us to find the required parameter.
Complete step by step solution:
We will show the given circuit and name the different parameters in the diagram as shown below:
From the circuit, there are two loops i.e. ABCDEA and HCDFGH.
Now, to calculate the unknown parameters, we will use Kirchhoff's voltage law for both loops separately. We will calculate each voltage drop in a loop and put it equal to the voltage in the circuit.
For loop ABCDEA,
\[
\Rightarrow 2{i_1} + 2\left( {{i_1} + {i_2}} \right) = 2 \\
\Rightarrow 2{i_1} + 2{i_1} + 2{i_2} = 2 \\
\Rightarrow 4{i_1} + 2{i_2} = 2 \\
\Rightarrow 2{i_1} + 2{i_2} = 1...\left( 1 \right) \\
\]
For loop HCDFGH,
$
\Rightarrow 2\left( {{i_1} + {i_2}} \right) + 2{i_2} = 2 \\
\Rightarrow 2{i_1} + 2{i_2} + 2{i_2} = 2 \\
\Rightarrow 2{i_1} + 4{i_2} = 2 \\
\Rightarrow {i_1} + 2{i_2} = 1...\left( 2 \right) \\
$
From the equation (1) and (2),
$
\Rightarrow {i_1} + 2\left( {1 - 2{i_1}} \right) = 1 \\
\Rightarrow - 3{i_1} = - 1 \\
\Rightarrow {i_1} = \dfrac{1}{3}A \\
$
On solving,
$
\Rightarrow {i_2} = 1 - 2\left( {\dfrac{1}{3}} \right) \\
\Rightarrow {i_2} = \dfrac{1}{3}A \\
$
Thus, we can calculate the ammeter reading by adding the both currents.
$
i = {i_1} + {i_2} \\
\Rightarrow i = \dfrac{1}{3} + \dfrac{1}{3} \\
\Rightarrow i = \dfrac{2}{3}A \\
$
Therefore, the ammeter reading is $\dfrac{2}{3}A$ .
Hence, the correct option is (C).
Note: In the given question, we need to analyse the circuit and find the law which will help us to find the unknown parameter. For any circuit, we have to look for nodes or loops which are given. After that we can apply Kirchhoff's current law if nodes are given or Kirchhoff’s voltage law if loops are given. The equations for voltage drop and node current will lead us to find the required parameter.
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