
The angular shape of ozone molecule \[{O_3}\] consists of:
A. 1 sigma and 1 pi bonds
B. 2 sigma and 1 pi bonds
C. 1 sigma and 2 pi bonds
D. 2 sigma and 2 pi bonds
Answer
128.1k+ views
Hint: Oxygen molecule has valency of -2. That is why it can form two sigma bonds with the other atoms. It has three lone pairs to form pi bonds with other atoms. Ozone has all three oxygen atoms and it’s a dihedral molecule with \[s{p^2}\] hybridisation.
Complete step-by-step answer:
The Lewis structure for ozone \[{O_3}\] consists of a central oxygen atom that has a double bond to one of the outer oxygen atoms and a single bond to the other oxygen atom. Lewis structure is based on the octet rule which states that there should be eight electrons in the outermost shell or orbit of an atom for the molecule to be stable.
Here, the lone pair on the central atom repels the electrons in the two side bonds present, forcing the atom to adopt a bent molecular geometry. Expected geometry is the trigonal planar, where O-O-O bond angle to be \[{120^o}\]. However, as per the context of the VSEPR model, lone pairs of electrons are considered slightly more repulsive than bonding pairs of electrons due to their closer proximity to the central atom. Therefore, the O-O-O angle is slightly less than \[{120^o}\] i.e. \[{116.8^o}\].
There are six valence electrons for each molecule of Oxygen in ozone and thus the total number of valence electrons is \[6 \times 3 = 18\]. As the octet rule applies, the central atom should have eight electrons in its outer shell. So, one molecule of the Oxygen is in the centre with the other two on the opposite sides of it.
The central atom has only one lone pair of electrons which is making it stable due to the eight electrons in its outermost orbit. To satisfy the octet rule, central atom requires to form a double bond on either of its sides with an Oxygen molecule. As both the atoms of Oxygen on sides have the same electronegativity and structure, the double bond keeps on shifting from both and results in resonance.
Therefore, the structure of Ozone is unique because the central atom has one double bond and one single bond with its neighbouring oxygen molecules which keeps interchanging their positions, and hence the angular shape of the ozone molecule has 2 sigma bonds and one pi bond.

Hence, the correct option is (B).
Note: Ozone molecule is polar because the distribution of electrons across the molecule is uneven. This leads to less electron density on the central atom. The negative half charge on the two side oxygen atoms and +1 formal charge on the central atom makes it polar.
Complete step-by-step answer:
The Lewis structure for ozone \[{O_3}\] consists of a central oxygen atom that has a double bond to one of the outer oxygen atoms and a single bond to the other oxygen atom. Lewis structure is based on the octet rule which states that there should be eight electrons in the outermost shell or orbit of an atom for the molecule to be stable.
Here, the lone pair on the central atom repels the electrons in the two side bonds present, forcing the atom to adopt a bent molecular geometry. Expected geometry is the trigonal planar, where O-O-O bond angle to be \[{120^o}\]. However, as per the context of the VSEPR model, lone pairs of electrons are considered slightly more repulsive than bonding pairs of electrons due to their closer proximity to the central atom. Therefore, the O-O-O angle is slightly less than \[{120^o}\] i.e. \[{116.8^o}\].
There are six valence electrons for each molecule of Oxygen in ozone and thus the total number of valence electrons is \[6 \times 3 = 18\]. As the octet rule applies, the central atom should have eight electrons in its outer shell. So, one molecule of the Oxygen is in the centre with the other two on the opposite sides of it.
The central atom has only one lone pair of electrons which is making it stable due to the eight electrons in its outermost orbit. To satisfy the octet rule, central atom requires to form a double bond on either of its sides with an Oxygen molecule. As both the atoms of Oxygen on sides have the same electronegativity and structure, the double bond keeps on shifting from both and results in resonance.
Therefore, the structure of Ozone is unique because the central atom has one double bond and one single bond with its neighbouring oxygen molecules which keeps interchanging their positions, and hence the angular shape of the ozone molecule has 2 sigma bonds and one pi bond.

Hence, the correct option is (B).
Note: Ozone molecule is polar because the distribution of electrons across the molecule is uneven. This leads to less electron density on the central atom. The negative half charge on the two side oxygen atoms and +1 formal charge on the central atom makes it polar.
Recently Updated Pages
Difference Between Vapor and Gas: JEE Main 2024

Area of an Octagon Formula - Explanation, and FAQs

Difference Between Solute and Solvent: JEE Main 2024

Absolute Pressure Formula - Explanation, and FAQs

Carbon Dioxide Formula - Definition, Uses and FAQs

Charle's Law Formula - Definition, Derivation and Solved Examples

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Mains 2025 Correction Window Date (Out) – Check Procedure and Fees Here!

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

NCERT Solutions for Class 11 Chemistry Chapter 8 Organic Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 6 Equilibrium
