
The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit?

A) $1.71\,A$
B) $2.0\,A$
C) $2.31\,A$
D) $1.33\,A$
Answer
139.8k+ views
Hint: The diode is forward biased if the positive terminal is connected to $P$ side and the negative terminal is connected to $N$ side of the diode. The condition is opposite for the reverse biased. Calculate the equivalent resistance from the circuit and apply in the ohm’s law to find the value of the current.
Formula used:
The ohm’s law is given by
$V = IR$
Where $V$ is the voltage developed across the circuit, $I$ is the current flowing through the circuit and $R$ is the equivalent resistance of the circuit.
Complete step by step solution:
From the given circuit diagram, it is clear that the diode ${D_1}$ is forward biased and the diode ${D_2}$ is reverse biased in nature. Hence ${D_2}$ has no current flows through it where ${D_1}$ has some amount of current flowing through it due to the changes in the value of the resistance for both. Since no current flows through the diode ${D_2}$, its resistance is not considered for calculating the equivalent resistance of the circuit.
${R_{eq}} = 3 + 4 = 7\,\Omega $
The value of the equivalent resistance is obtained as $7\,\Omega $ .
Using the formula of the ohm’s law,
$V = IR$
Rearranging the above formula, we get
$I = \dfrac{V}{R}$
Substituting the known values in it,
$\Rightarrow I = \dfrac{{12}}{7} = 1.71\,A$
Hence the current of the circuit is calculated as $1.71\,A$ .
Thus the option (A) is correct.
Note: Remember that if the diode in the circuit is reversely biased, then it will have the infinite resistance and so no current flows through it. If the diode is forward biased, the resistance of this diode will be zero and hence maximum current flows through it.
Formula used:
The ohm’s law is given by
$V = IR$
Where $V$ is the voltage developed across the circuit, $I$ is the current flowing through the circuit and $R$ is the equivalent resistance of the circuit.
Complete step by step solution:
From the given circuit diagram, it is clear that the diode ${D_1}$ is forward biased and the diode ${D_2}$ is reverse biased in nature. Hence ${D_2}$ has no current flows through it where ${D_1}$ has some amount of current flowing through it due to the changes in the value of the resistance for both. Since no current flows through the diode ${D_2}$, its resistance is not considered for calculating the equivalent resistance of the circuit.
${R_{eq}} = 3 + 4 = 7\,\Omega $
The value of the equivalent resistance is obtained as $7\,\Omega $ .
Using the formula of the ohm’s law,
$V = IR$
Rearranging the above formula, we get
$I = \dfrac{V}{R}$
Substituting the known values in it,
$\Rightarrow I = \dfrac{{12}}{7} = 1.71\,A$
Hence the current of the circuit is calculated as $1.71\,A$ .
Thus the option (A) is correct.
Note: Remember that if the diode in the circuit is reversely biased, then it will have the infinite resistance and so no current flows through it. If the diode is forward biased, the resistance of this diode will be zero and hence maximum current flows through it.
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

How to find Oxidation Number - Important Concepts for JEE

How Electromagnetic Waves are Formed - Important Concepts for JEE

Electrical Resistance - Important Concepts and Tips for JEE

Average Atomic Mass - Important Concepts and Tips for JEE

Chemical Equation - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

A point charge + 20mu C is at a distance 6cm directly class 12 physics JEE_Main

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

A conducting loop carrying a current is placed in a class 12 physics JEE_Main
