The coefficient of thermal conductivity of copper, mercury and glass respectively are ${K_{C,}}{K_m}$ and ${K_g}$ such that ${K_C} > {K_m} > {K_g}$. If the same quantity of heat is flowing per second per unit area through each and corresponding temperature gradient are ${X_c},{X_m}$ and ${X_g}$. Then:
(A) ${X_c} = {X_m} = {X_g}$
(B) ${X_c} > {X_m} > {X_g}$
(C) ${X_c} < {X_m} < {X_g}$
(D) ${X_m} < {X_c} < {X_g}$
Answer
Verified
122.7k+ views
Hint We know that the law of conduction of heat is also known as the Fourier’s law. We know that the heat transfer is classified into various mechanisms, which are thermal conduction, thermal conduction, thermal radiation, and the transfer of energy by the phase changes. This is the concept which is used to solve this answer. We should consider the fact that engineers also consider the transfer of mass of differing chemical species, either cold, or hot, to reach the required amount of heat transfer.
Complete step by step answer
We should know that from the basis law of conduction which is Fourier’s law that:
$Q = - KA\left( {\dfrac{{dT}}{{dx}}} \right)$
Where the $\dfrac{{dT}}{{dx}}$is the temperature gradient
So, K is inversely proportional to the temperature gradient.
Hence, we can say that:
${K_{metal}} > {K_{liquid}} > {K_{gas}}$
Now we can write that:
${X_{metal}} < {X_{liquid}} < {X_{gas}}$or we can say,
${X_{copper}} < {X_{mercury}} < {X_{glass}}$
Hence the ceramics material has greater conductivity as compared to that of gas. So it can said that the same quantity of heat is flowing per second per unit area through each and corresponding temperature gradient are ${X_c},{X_m}$ and ${X_g}$, then ${X_c} < {X_m} < {X_g}$.
Hence the correct answer is option C.
Note The law of heat conduction is known as the explanation which states that the rate of transfer of heat through a material is proportional to the negative gradient in the temperature and to the area, at the right angles to that of the gradient, through which the heat will flow.
The basic idea of the law states that the heat flux vector will be proportional to the negative vector gradient of the temperature. The process of conduction is greater in the solids because of the network of the relatively close fixed spatial relationships between the atoms to help the transfer of the energy between the vibration.
Complete step by step answer
We should know that from the basis law of conduction which is Fourier’s law that:
$Q = - KA\left( {\dfrac{{dT}}{{dx}}} \right)$
Where the $\dfrac{{dT}}{{dx}}$is the temperature gradient
So, K is inversely proportional to the temperature gradient.
Hence, we can say that:
${K_{metal}} > {K_{liquid}} > {K_{gas}}$
Now we can write that:
${X_{metal}} < {X_{liquid}} < {X_{gas}}$or we can say,
${X_{copper}} < {X_{mercury}} < {X_{glass}}$
Hence the ceramics material has greater conductivity as compared to that of gas. So it can said that the same quantity of heat is flowing per second per unit area through each and corresponding temperature gradient are ${X_c},{X_m}$ and ${X_g}$, then ${X_c} < {X_m} < {X_g}$.
Hence the correct answer is option C.
Note The law of heat conduction is known as the explanation which states that the rate of transfer of heat through a material is proportional to the negative gradient in the temperature and to the area, at the right angles to that of the gradient, through which the heat will flow.
The basic idea of the law states that the heat flux vector will be proportional to the negative vector gradient of the temperature. The process of conduction is greater in the solids because of the network of the relatively close fixed spatial relationships between the atoms to help the transfer of the energy between the vibration.
Recently Updated Pages
The ratio of the diameters of two metallic rods of class 11 physics JEE_Main
What is the difference between Conduction and conv class 11 physics JEE_Main
Mark the correct statements about the friction between class 11 physics JEE_Main
Find the acceleration of the wedge towards the right class 11 physics JEE_Main
A standing wave is formed by the superposition of two class 11 physics JEE_Main
Derive an expression for work done by the gas in an class 11 physics JEE_Main
Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Login 2045: Step-by-Step Instructions and Details
Class 11 JEE Main Physics Mock Test 2025
JEE Main Chemistry Question Paper with Answer Keys and Solutions
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes: CBSE Physics Chapter 1
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line