Answer
Verified
114.3k+ views
Hint : We know that Maxwell’s distribution plot is a plot between the fraction of molecule and speed of molecule at standard temperature. The area under the curve represents the number of molecules. If we heat the gas the peak of the curve will be shifted right because the average speed of the molecule will increase.
Complete step by step solution:
The Maxwell-Boltzmann plot of distribution is given below.
The most probable speed corresponds to the top of the distribution curve because a greater fraction of molecules will have this speed. It is expressed as ${\nu _{mp}} = \sqrt {\dfrac{{2{k_B}T}}{m}} $ where ${k_B}$is Boltzmann constant and $T$ is temperature. We can say that from the equation that the most probable velocity of gas molecules increases with the increase in temperature. At higher temperature, large numbers of molecules will acquire greater amounts of kinetic energy and they move very fast hence their speed increases. The curve also flattens with the increase of temperature. At the same temperature molecules of gas will possess the same kinetic energy. So we can say that when the temperature increases the most probable speed of molecules also increases. Therefore statement A is correct .
Note: We know that we can calculate the most probable speed, the average speed and root mean square speed with the help of Maxwell-Boltzmann equation which gives relation with temperature. Here in the problem we have found out the correct statement with the help of the equation of most probable speed. Second statement is incorrect because it is not possible to decrease the fraction of molecules with the rise of temperature.
Complete step by step solution:
The Maxwell-Boltzmann plot of distribution is given below.
The most probable speed corresponds to the top of the distribution curve because a greater fraction of molecules will have this speed. It is expressed as ${\nu _{mp}} = \sqrt {\dfrac{{2{k_B}T}}{m}} $ where ${k_B}$is Boltzmann constant and $T$ is temperature. We can say that from the equation that the most probable velocity of gas molecules increases with the increase in temperature. At higher temperature, large numbers of molecules will acquire greater amounts of kinetic energy and they move very fast hence their speed increases. The curve also flattens with the increase of temperature. At the same temperature molecules of gas will possess the same kinetic energy. So we can say that when the temperature increases the most probable speed of molecules also increases. Therefore statement A is correct .
Note: We know that we can calculate the most probable speed, the average speed and root mean square speed with the help of Maxwell-Boltzmann equation which gives relation with temperature. Here in the problem we have found out the correct statement with the help of the equation of most probable speed. Second statement is incorrect because it is not possible to decrease the fraction of molecules with the rise of temperature.
Recently Updated Pages
JEE Colleges - Detailed Description of Top JEE Colleges
JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key
Geostationary Satellites and Geosynchronous Satellites for JEE
Complex Numbers - Important Concepts and Tips for JEE
JEE Main 2023 (February 1st Shift 2) Maths Question Paper with Answer Key
JEE Main 2022 (July 25th Shift 2) Physics Question Paper with Answer Key
Trending doubts
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main Login 2045: Step-by-Step Instructions and Details
Which of the following gem diols is stable A CH3 Cleft class 12 chemistry JEE_Main
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
Collision - Important Concepts and Tips for JEE
Ideal and Non-Ideal Solutions Raoult's Law - JEE
Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 8 Aldehydes Ketones and Carboxylic Acids
NCERT Solutions for Class 12 Chemistry Chapter 3 Chemical Kinetics
NCERT Solutions for Class 12 Chemistry In Hindi Chapter 10 Haloalkanes and Haloarenes In Hindi Mediem
Free Radical Substitution Mechanism of Alkanes for JEE Main 2025
Current Loop as Magnetic Dipole and Its Derivation for JEE
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Keys & Solutions