
The count rate of a Geiger- Muller counter for the radiation of a radioactive material of half-life of 30 minutes decreases to $5s^{-1}$ after 2 hours. The initial count rate was
A. $25 s^{-1}$
B. $20 s^{-1}$
C. $80 s^{-1}$
D. $625 s^{-1}$
Answer
232.8k+ views
Hint: The Geiger-Muller counter is used for measuring the radiation emitted by a radioactive material. Half-life of the material is also given. After 2 hrs it rate decreases to $5s^{-1}$. We have to find the initial rate using the given data.
Formula used:
We can use the same formula connecting amount of the original sample, remaining amount of the sample, half-life and time taken for decay:
$\dfrac{N}{N_{0}}=\left(\dfrac{1}{2}\right)^{\dfrac{t}{T}}$
Where $\mathrm{N}$ is the amount of sample remaining after $t$ time or final rate.
$N_{0}$ is the original amount of sample or initial rate.
$\mathrm{T}$ is the half-life of the radioactive material.
Complete answer:
We have a radioactive material of half-life 30 minutes. And the count rate of Gieger-Muller counter
decreases to $5 s^{-1}$ after 2 hrs. With these data we have to find the initial rate shown in
Geiger-Muller counter.
In order to find the initial rate, we have the equation connecting all the known factors in question as:
$\dfrac{N}{N_{0}}=\left(\dfrac{1}{2}\right)^{\dfrac{t}{T}}$
Here we have to find $N_{0}$ that is the initial count rate.
Final count rate, $N=5 s^{-1}$
Half-life of the radioactive material, $T=30$ minutes
Time taken, $t=2 h r s=120$ minutes
On substituting the values in the equation, we get:
$\dfrac{5}{N_{0}}=\left(\dfrac{1}{2}\right)^{\dfrac{120}{30}}$
Therefore, initial count rate is:
$N_{0}=\dfrac{5}{\left(\dfrac{1}{2}\right)^{4}}=5 \times 2^{4}=16 \times 5=80 s^{-1}$
Thus, option (D) is correct.
Additional information: The Geiger-Muller counter is an instrument which measures and detects ionization produced by radiation. It can count particles at rates up to 10,000 per second. Radioactive particles produce radiation when it decays. So, it can also be used to measure decay of radioactive materials.
Note: Amount here is taken as the rate since the rate is given in the question. Radioactivity measurement means how much of radioactivity has decayed. So, we can replace the amount with the rate. Don’t forget to convert the unit of time before calculating.
Formula used:
We can use the same formula connecting amount of the original sample, remaining amount of the sample, half-life and time taken for decay:
$\dfrac{N}{N_{0}}=\left(\dfrac{1}{2}\right)^{\dfrac{t}{T}}$
Where $\mathrm{N}$ is the amount of sample remaining after $t$ time or final rate.
$N_{0}$ is the original amount of sample or initial rate.
$\mathrm{T}$ is the half-life of the radioactive material.
Complete answer:
We have a radioactive material of half-life 30 minutes. And the count rate of Gieger-Muller counter
decreases to $5 s^{-1}$ after 2 hrs. With these data we have to find the initial rate shown in
Geiger-Muller counter.
In order to find the initial rate, we have the equation connecting all the known factors in question as:
$\dfrac{N}{N_{0}}=\left(\dfrac{1}{2}\right)^{\dfrac{t}{T}}$
Here we have to find $N_{0}$ that is the initial count rate.
Final count rate, $N=5 s^{-1}$
Half-life of the radioactive material, $T=30$ minutes
Time taken, $t=2 h r s=120$ minutes
On substituting the values in the equation, we get:
$\dfrac{5}{N_{0}}=\left(\dfrac{1}{2}\right)^{\dfrac{120}{30}}$
Therefore, initial count rate is:
$N_{0}=\dfrac{5}{\left(\dfrac{1}{2}\right)^{4}}=5 \times 2^{4}=16 \times 5=80 s^{-1}$
Thus, option (D) is correct.
Additional information: The Geiger-Muller counter is an instrument which measures and detects ionization produced by radiation. It can count particles at rates up to 10,000 per second. Radioactive particles produce radiation when it decays. So, it can also be used to measure decay of radioactive materials.
Note: Amount here is taken as the rate since the rate is given in the question. Radioactivity measurement means how much of radioactivity has decayed. So, we can replace the amount with the rate. Don’t forget to convert the unit of time before calculating.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

