Answer
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Hint: When a body is partially or completely immersed in a fluid, a force acts on it in the upward direction which is called force of buoyancy or buoyant force. It is given by ${F_B} = \sigma \times V \times g$ where $\sigma $ is the density of the body, $V$ is the volume of the body in consideration and $g$ is the acceleration due to gravity.
Due to this buoyant force, the body loses some of its weight which is equal to the weight of the fluid displaced by the immersed part of the body.
Complete step by step answer
As given in the question, the ice is partially immersed in water.
We know that when a body is partially or completely immersed in a fluid, a force acts on it in the upward direction which is called force of buoyancy or buoyant force. It is given by ${F_B} = \sigma \times V \times g$ where $\sigma $ is the density of the body, $V$ is the volume of the body in consideration and $g$ is the acceleration due to gravity.
And according to the Archimedes’ Principle, due to this buoyant force, the body loses some of its weight which is equal to the weight of the fluid displaced by the immersed part of the body.
Let $f$ be the fraction of volume of the ice that is inside the water. Then $\left( {1 - f} \right)$ will be the fraction of volume above water. We know that the density of water $\rho = 1000{\text{ kg/}}{{\text{m}}^3}$ and the density of ice is given $\sigma = 917{\text{ kg/}}{{\text{m}}^3}$ . Now, we apply Archimedes’ Principle to find the answer i.e.
${\text{Buoyant Force }} = {\text{ Displaced weight of water}}$
$\sigma \times \left( {1 - f} \right) \times V \times g = \rho \times f \times V \times g$
On substituting the value and simplifying we have
\[917 \times \left( {1 - f} \right) = 1000 \times f\]
On further solving we have
$f = 0.917$
Therefore, the fraction of volume of the ice above water is $\left( {1 - f} \right) = 1 - 0.917 = 0.083$
Hence, option A is correct.
Note: The Archimedes’ Principle has numerous important applications in our life. It is used in designing the ships, boats and other water bodies. They are also used in producing Hydrometers which are used to measure density of different liquids.
Due to this buoyant force, the body loses some of its weight which is equal to the weight of the fluid displaced by the immersed part of the body.
Complete step by step answer
As given in the question, the ice is partially immersed in water.
We know that when a body is partially or completely immersed in a fluid, a force acts on it in the upward direction which is called force of buoyancy or buoyant force. It is given by ${F_B} = \sigma \times V \times g$ where $\sigma $ is the density of the body, $V$ is the volume of the body in consideration and $g$ is the acceleration due to gravity.
And according to the Archimedes’ Principle, due to this buoyant force, the body loses some of its weight which is equal to the weight of the fluid displaced by the immersed part of the body.
Let $f$ be the fraction of volume of the ice that is inside the water. Then $\left( {1 - f} \right)$ will be the fraction of volume above water. We know that the density of water $\rho = 1000{\text{ kg/}}{{\text{m}}^3}$ and the density of ice is given $\sigma = 917{\text{ kg/}}{{\text{m}}^3}$ . Now, we apply Archimedes’ Principle to find the answer i.e.
${\text{Buoyant Force }} = {\text{ Displaced weight of water}}$
$\sigma \times \left( {1 - f} \right) \times V \times g = \rho \times f \times V \times g$
On substituting the value and simplifying we have
\[917 \times \left( {1 - f} \right) = 1000 \times f\]
On further solving we have
$f = 0.917$
Therefore, the fraction of volume of the ice above water is $\left( {1 - f} \right) = 1 - 0.917 = 0.083$
Hence, option A is correct.
Note: The Archimedes’ Principle has numerous important applications in our life. It is used in designing the ships, boats and other water bodies. They are also used in producing Hydrometers which are used to measure density of different liquids.
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