
The force between two short electric dipoles placed on the same axis at a distance $R$ varies as?
A) ${R^{ - 1}}$
B) ${R^{ - 2}}$
C) ${R^{ - 3}}$
D) ${R^{ - 4}}$
Answer
225k+ views
Hint: Force acting between two electric dipoles depends on the potential energy of the electric dipoles. If the dipole moment is constant, the net force is zero, because the charges get pulled equally and oppositely.
Complete step by step solution:
Here it is given in the question that two short electric dipoles on the same axis are at a distance of $R$ from each other. We are asked to find how the force acting in between them varies in the term of $R$.
We know the electric produced by an electric dipole in a n axial position is given by the equation,
$E = \dfrac{{2KP}}{{{R^3}}}$
Where, $K$ is the electrostatic constant.
The value of the electrostatic constant is given by, $K = \dfrac{1}{{4\pi {\varepsilon _0}}}$
$P$ is the electric dipole moment.
Now, potential energy of the dipole, $U = - PE\cos \theta $
Where, $\theta $ is the angle between the electric field and dipole, here it is placed in the same axis and thus the angle between the electric field and dipole will be zero.
$ \Rightarrow U = - PE\cos 0$
$ \therefore U = - PE$
Substituting the value of $E$ in this equation, we get,
$ \therefore U = - P \times \dfrac{{2KP'}}{{{R^3}}}$
We need to find the value of force acting between the two electric dipoles.
Force acting is given by the equation,
$F = - \dfrac{{dU}}{{dR}}$
Applying the value of the potential energy to this equation, we get,
$ \Rightarrow F = - \dfrac{d}{{dR}}\left( {\dfrac{{ - 2KPP'}}{{{R^3}}}} \right)$
$ \Rightarrow F = 2KPP'\dfrac{d}{{dR}}\left( {\dfrac{1}{{{R^3}}}} \right)$
$ \therefore F = - 6KPP'\dfrac{1}{{{R^4}}}$
There for the force between two short electric dipole placed on the same axis at a distance $R$ is proportional to $\dfrac{1}{{{R^4}}}$ or ${R^{ - 4}}.$
So the final answer is option (D), ${R^{ - 4}}$.
Note: An electric dipole is defined as a couple of opposite charges $q$ and $ - q$separated by a distance $R$. By default, the direction of electric dipoles in space is always from negative charge $ - q$ to positive charge $q$. The midpoint $q$ and $ - q$ is called the centre of the dipole.
Complete step by step solution:
Here it is given in the question that two short electric dipoles on the same axis are at a distance of $R$ from each other. We are asked to find how the force acting in between them varies in the term of $R$.
We know the electric produced by an electric dipole in a n axial position is given by the equation,
$E = \dfrac{{2KP}}{{{R^3}}}$
Where, $K$ is the electrostatic constant.
The value of the electrostatic constant is given by, $K = \dfrac{1}{{4\pi {\varepsilon _0}}}$
$P$ is the electric dipole moment.
Now, potential energy of the dipole, $U = - PE\cos \theta $
Where, $\theta $ is the angle between the electric field and dipole, here it is placed in the same axis and thus the angle between the electric field and dipole will be zero.
$ \Rightarrow U = - PE\cos 0$
$ \therefore U = - PE$
Substituting the value of $E$ in this equation, we get,
$ \therefore U = - P \times \dfrac{{2KP'}}{{{R^3}}}$
We need to find the value of force acting between the two electric dipoles.
Force acting is given by the equation,
$F = - \dfrac{{dU}}{{dR}}$
Applying the value of the potential energy to this equation, we get,
$ \Rightarrow F = - \dfrac{d}{{dR}}\left( {\dfrac{{ - 2KPP'}}{{{R^3}}}} \right)$
$ \Rightarrow F = 2KPP'\dfrac{d}{{dR}}\left( {\dfrac{1}{{{R^3}}}} \right)$
$ \therefore F = - 6KPP'\dfrac{1}{{{R^4}}}$
There for the force between two short electric dipole placed on the same axis at a distance $R$ is proportional to $\dfrac{1}{{{R^4}}}$ or ${R^{ - 4}}.$
So the final answer is option (D), ${R^{ - 4}}$.
Note: An electric dipole is defined as a couple of opposite charges $q$ and $ - q$separated by a distance $R$. By default, the direction of electric dipoles in space is always from negative charge $ - q$ to positive charge $q$. The midpoint $q$ and $ - q$ is called the centre of the dipole.
Recently Updated Pages
JEE Main 2025-26 Experimental Skills Mock Test – Free Practice

JEE Main 2025-26: Magnetic Effects of Current & Magnetism Mock Test

JEE Main 2025-26 Atoms and Nuclei Mock Test – Free Practice Online

JEE Main Mock Test 2025-26: Optics Chapter Practice Online

The work done in slowly moving an electron of charge class 12 physics JEE_Main

The value of the resistor RS needed in the DC voltage class 12 physics JEE_Main

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Atomic Structure for Beginners

Understanding Electromagnetic Waves and Their Importance

