
The fundamental frequency of an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe is
(A) 12.5cm
(B) 13.2cm
(C) 16cm
(D) 8cm
Answer
143.1k+ views
Hint We should know that by the term fundamental frequency we mean the lowest frequency at which a medium will oscillate freely. Based on this concept we have to solve this question.
Complete step by step answer
We know that the fundamental frequency for an open organ pipe is $\dfrac{{\text{V}}}{{{\text{2l}}}}$
Also, we can therefore derive the frequency of third harmonic for closed organ pipe as $\dfrac{{{\text{3V}}}}{{{\text{4}}{{\text{l}}_1}}}$
Since both are given as equal in the question,
We can derive that,
$\dfrac{{\text{V}}}{{{\text{2l}}}} = \dfrac{{{\text{3V}}}}{{{\text{4}}{{\text{l}}_1}}}$
$\Rightarrow {\text{l = }}\dfrac{{{\text{2}}{{\text{l}}_1}}}{3}$
$\Rightarrow {\text{l = }}\dfrac{{2 \times 20}}{3}$
$\therefore {\text{l = 13}}{\text{.2cm}}$
Therefore, the correct answer is Option B.
Note The fundamental frequency is important because it will give us an idea about the strongest audible pitch reference which is predominant in any kind of complex waveform.
Complete step by step answer
We know that the fundamental frequency for an open organ pipe is $\dfrac{{\text{V}}}{{{\text{2l}}}}$
Also, we can therefore derive the frequency of third harmonic for closed organ pipe as $\dfrac{{{\text{3V}}}}{{{\text{4}}{{\text{l}}_1}}}$
Since both are given as equal in the question,
We can derive that,
$\dfrac{{\text{V}}}{{{\text{2l}}}} = \dfrac{{{\text{3V}}}}{{{\text{4}}{{\text{l}}_1}}}$
$\Rightarrow {\text{l = }}\dfrac{{{\text{2}}{{\text{l}}_1}}}{3}$
$\Rightarrow {\text{l = }}\dfrac{{2 \times 20}}{3}$
$\therefore {\text{l = 13}}{\text{.2cm}}$
Therefore, the correct answer is Option B.
Note The fundamental frequency is important because it will give us an idea about the strongest audible pitch reference which is predominant in any kind of complex waveform.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE

How Electromagnetic Waves are Formed - Important Concepts for JEE

Electrical Resistance - Important Concepts and Tips for JEE

Average Atomic Mass - Important Concepts and Tips for JEE

Chemical Equation - Important Concepts and Tips for JEE

Concept of CP and CV of Gas - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Degree of Dissociation and Its Formula With Solved Example for JEE

Physics Average Value and RMS Value JEE Main 2025

Other Pages
Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry
