
The invariable volume of a brass sphere is \[1000\]\[cc\] at \[{0^0}C\]. Its volume at \[{100^0}C\] is :
\[\left( {\alpha = 18 \times {{10}^{ - 6}}{/^0}C} \right)\]
A) \[1000\]\[cc\]
B) \[994.6\]\[cc\]
C) \[1005.4\]\[cc\]
D) \[100.54\]\[cc\]
Answer
219.9k+ views
Hint: We know that material is a good conductor of heat and electricity. When temperature increases, then conductivity also changes. When temperature changes, the volume of material will change.
Formula used: We are calculating volume at \[{100^0}C\] by this formula:
Final volume = initial volume \[\times \left( {1 + \gamma \Delta T} \right)\]. In question, \[\alpha \] is given. The relation between \[\alpha \] and \[\gamma \] is given as \[\gamma = 3\alpha \].
Complete step by step solution:
Given: Volume of a brass sphere at \[{0^0}C\] =\[1000\]\[cc\],\[\alpha = 18 \times {10^{ - 6}}{/^0}C\]
At \[{100^0}C\], volume of a brass sphere is given by following formula
Final volume = initial volume \[\times \left( {1 + \gamma \Delta T} \right)\]
Final volume = initial volume \[\times \left( {1 + 3\alpha \Delta T} \right)\]
Here: Initial volume is define as volume at \[{0^0}C\]=\[1000\]\[cc\]
Final volume is define as volume at \[{100^0}C\]
So, we can calculate, Final volume = \[1000 \times \left( {1 + 3 \times 8 \times {{10}^{ - 6}} \times 100} \right)\]
\[ \Rightarrow Final{\text{ }}volume = 1005.4\]
Hence, volume at \[{100^0}C\] = \[1005.4\] \[cc\]
Hence, the correct option is (C).
Additional information: Thermal expansion refers to a fractional change in size of a material to a change in temperature. This fractional change of size may be one of the following type:
(1) change in length compared to original length is called linear expansion
(2) change in the area compared to its original area is called areal expansion.
(3) change in volume compared to its original volume is called volumetric expansion. It is also called cubical expansion.
A coefficient of thermal expansion is a ratio. This coefficient is given as, the ratio of the fractional change in length, area or original volume of a material to its change in temperature.
Note: Students must consider that here the value of linear expansion, \[\alpha \] is given .In formula cubic expansion, \[\gamma \] is used. We know that the relation between cubic and linear expansion is given by Cubical expansion = 3 \[\times\] linear expansion. Students first find the value of cubic expansion. Then put this value in a formula to find the final volume.
Formula used: We are calculating volume at \[{100^0}C\] by this formula:
Final volume = initial volume \[\times \left( {1 + \gamma \Delta T} \right)\]. In question, \[\alpha \] is given. The relation between \[\alpha \] and \[\gamma \] is given as \[\gamma = 3\alpha \].
Complete step by step solution:
Given: Volume of a brass sphere at \[{0^0}C\] =\[1000\]\[cc\],\[\alpha = 18 \times {10^{ - 6}}{/^0}C\]
At \[{100^0}C\], volume of a brass sphere is given by following formula
Final volume = initial volume \[\times \left( {1 + \gamma \Delta T} \right)\]
Final volume = initial volume \[\times \left( {1 + 3\alpha \Delta T} \right)\]
Here: Initial volume is define as volume at \[{0^0}C\]=\[1000\]\[cc\]
Final volume is define as volume at \[{100^0}C\]
So, we can calculate, Final volume = \[1000 \times \left( {1 + 3 \times 8 \times {{10}^{ - 6}} \times 100} \right)\]
\[ \Rightarrow Final{\text{ }}volume = 1005.4\]
Hence, volume at \[{100^0}C\] = \[1005.4\] \[cc\]
Hence, the correct option is (C).
Additional information: Thermal expansion refers to a fractional change in size of a material to a change in temperature. This fractional change of size may be one of the following type:
(1) change in length compared to original length is called linear expansion
(2) change in the area compared to its original area is called areal expansion.
(3) change in volume compared to its original volume is called volumetric expansion. It is also called cubical expansion.
A coefficient of thermal expansion is a ratio. This coefficient is given as, the ratio of the fractional change in length, area or original volume of a material to its change in temperature.
Note: Students must consider that here the value of linear expansion, \[\alpha \] is given .In formula cubic expansion, \[\gamma \] is used. We know that the relation between cubic and linear expansion is given by Cubical expansion = 3 \[\times\] linear expansion. Students first find the value of cubic expansion. Then put this value in a formula to find the final volume.
Recently Updated Pages
Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

States of Matter Chapter For JEE Main Chemistry

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

