
The latent heat vaporization of water is 2240 J/gm. if the work done in the process of expansion of 1 g is 168 J, then an increase in internal energy is
A. 2408 J
B. 2240 J
C. 2072 J
D. 1904 J
Answer
127.8k+ views
Hint: According to the First Law of Thermodynamics, the universe's energy content remains constant. Energy cannot be generated or destroyed, but it may be changed from one form to another. Mathematically expressed as $\Delta U = \Delta Q - \Delta W$ where W is the work done on or by the system, U is the internal energy and Q is the heat added or removed from the system.
Formula used:
1. $\Delta Q = \Delta U + \Delta W$
Where W is the work done on or by the system, U is the internal energy and Q is the heat added or removed from the system.
2. Q=mL
Where Q is the heat and m is the mass of the object and L is the latent heat of vaporization.
Complete step by step solution:
First let’s discuss the first law of thermodynamics. First Law of Thermodynamics states that the amount of energy in the universe is constant. Energy cannot be generated or destroyed, but it may be changed from one form to another. The law of conservation of energy is another name for this rule.
By using Q=mL and we are given that mass of water is 1g and L is 2240J/gm
Therefore, Q= 2240J
Now here in the question latent heat of vaporization which the heat energy required to turn a liquid into a gas. This heat energy is stored in the liquid's molecular bonds. When these bonds are broken, the heat energy is released and converted into kinetic energy, which causes the liquid to vaporize. So, we can say that it is the amount of heat transferred into the system. Next, look that the gas is expanding means work done by the system. So, we take it with a negative sign. If we put all the given values on the equation then we get.
$ \Delta U = \Delta Q - \Delta W$
$\Delta U = 2240 - 168 $
$\Delta U = 2072J $
Hence, the change in internal energy is 2072 J and our correct option is C.
Note: The universe's energy content is constant, according to the First Law of Thermodynamics. It is possible to change the shape of energy, but neither creation nor destruction are possible with it. Its mathematical expression is $\Delta Q = \Delta U + \Delta W$. When heat is transferred to the system then we take it with a positive sign and when work is done by the system then we take it negative. Similarly, we When heat is out from the system then we take it with a negative sign and when work is done on the system then we take it positive.
Formula used:
1. $\Delta Q = \Delta U + \Delta W$
Where W is the work done on or by the system, U is the internal energy and Q is the heat added or removed from the system.
2. Q=mL
Where Q is the heat and m is the mass of the object and L is the latent heat of vaporization.
Complete step by step solution:
First let’s discuss the first law of thermodynamics. First Law of Thermodynamics states that the amount of energy in the universe is constant. Energy cannot be generated or destroyed, but it may be changed from one form to another. The law of conservation of energy is another name for this rule.
By using Q=mL and we are given that mass of water is 1g and L is 2240J/gm
Therefore, Q= 2240J
Now here in the question latent heat of vaporization which the heat energy required to turn a liquid into a gas. This heat energy is stored in the liquid's molecular bonds. When these bonds are broken, the heat energy is released and converted into kinetic energy, which causes the liquid to vaporize. So, we can say that it is the amount of heat transferred into the system. Next, look that the gas is expanding means work done by the system. So, we take it with a negative sign. If we put all the given values on the equation then we get.
$ \Delta U = \Delta Q - \Delta W$
$\Delta U = 2240 - 168 $
$\Delta U = 2072J $
Hence, the change in internal energy is 2072 J and our correct option is C.
Note: The universe's energy content is constant, according to the First Law of Thermodynamics. It is possible to change the shape of energy, but neither creation nor destruction are possible with it. Its mathematical expression is $\Delta Q = \Delta U + \Delta W$. When heat is transferred to the system then we take it with a positive sign and when work is done by the system then we take it negative. Similarly, we When heat is out from the system then we take it with a negative sign and when work is done on the system then we take it positive.
Recently Updated Pages
Difference Between Vapor and Gas: JEE Main 2024

Area of an Octagon Formula - Explanation, and FAQs

Difference Between Solute and Solvent: JEE Main 2024

Absolute Pressure Formula - Explanation, and FAQs

Carbon Dioxide Formula - Definition, Uses and FAQs

Charle's Law Formula - Definition, Derivation and Solved Examples

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Login 2045: Step-by-Step Instructions and Details

Class 11 JEE Main Physics Mock Test 2025

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

JEE Mains 2025 Correction Window Date (Out) – Check Procedure and Fees Here!

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement
