Answer
Verified
99.9k+ views
Hint: As this problem comes under mechanics, it is possible to solve it if you know conservation laws. Here, conservation of angular momentum is used to solve the speed of a comet at the farthest distance. Conservation of angular momentum says that total angular momentum at any point remains constant.
Formula used:
\[V=\frac{rv}{R}\]
Where,
V=speed of comet at farthest distance.
R=maximum distance.
r=minimum distance.
Complete answer:
The orbit around the sun is elliptical. Let ‘r’ denote the minimum distance and ‘v’ denote the speed of the comet at the minimum distance. Let ‘R’ be the maximum distance and ‘V’ be the speed of the comet at farthest distance from sun and ‘m’ be the mass of the comet
From the conservation of angular momentum
Angular momentum at nearest point = Angular momentum at farthest point
\[mvr=mVR\]
Therefore, speed of comet at farthest distance is
\[V=\frac{rv}{R}\]
That is,
\[V=\frac{8\times {{10}^{10}}\times 6\times {{10}^{4}}}{1.6\times {{10}^{12}}}\]
On calculating we get the speed of comet as
\[V=3.0\times {{10}^{3}}m{{s}^{-1}}\]
Therefore, answer is (c).
Note: Here Kepler’s first law and second law is used. Kepler’s first law states that the path of revolution of the planet around the sun is elliptical. That is every revolving object has a point closer to the sun and farther to the sun. Kepler’s second law states that the radius vector sweeps equal area in equal intervals of time. That is for conserving angular momentum the speed of the planet nearer to the sun is high and at a point farther from the sun the speed of the planet is low. So this can be used to check your answer whether the answer we got is right or wrong.
Formula used:
\[V=\frac{rv}{R}\]
Where,
V=speed of comet at farthest distance.
R=maximum distance.
r=minimum distance.
Complete answer:
The orbit around the sun is elliptical. Let ‘r’ denote the minimum distance and ‘v’ denote the speed of the comet at the minimum distance. Let ‘R’ be the maximum distance and ‘V’ be the speed of the comet at farthest distance from sun and ‘m’ be the mass of the comet
From the conservation of angular momentum
Angular momentum at nearest point = Angular momentum at farthest point
\[mvr=mVR\]
Therefore, speed of comet at farthest distance is
\[V=\frac{rv}{R}\]
That is,
\[V=\frac{8\times {{10}^{10}}\times 6\times {{10}^{4}}}{1.6\times {{10}^{12}}}\]
On calculating we get the speed of comet as
\[V=3.0\times {{10}^{3}}m{{s}^{-1}}\]
Therefore, answer is (c).
Note: Here Kepler’s first law and second law is used. Kepler’s first law states that the path of revolution of the planet around the sun is elliptical. That is every revolving object has a point closer to the sun and farther to the sun. Kepler’s second law states that the radius vector sweeps equal area in equal intervals of time. That is for conserving angular momentum the speed of the planet nearer to the sun is high and at a point farther from the sun the speed of the planet is low. So this can be used to check your answer whether the answer we got is right or wrong.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main
Other Pages
The values of kinetic energy K and potential energy class 11 physics JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main
BF3 reacts with NaH at 450 K to form NaF and X When class 11 chemistry JEE_Main
Dependence of intensity of gravitational field E of class 11 physics JEE_Main
In the reaction of KMnO4 with H2C204 20 mL of 02 M class 12 chemistry JEE_Main
What torque will increase the angular velocity of a class 11 physics JEE_Main