The upper and lower fixed points of a faulty mercury thermometer are ${{210}^{{}^\circ }}F$and ${{34}^{{}^\circ }}F$ respectively. The correct temperature read by this thermometer is:
(A) ${{22}^{{}^\circ }}F$
(B) ${{80}^{{}^\circ }}F$
(C) ${{100}^{{}^\circ }}F$
(D) ${{122}^{{}^\circ }}F$
Answer
Verified
116.4k+ views
Hint: To answer this question we have to first know the formula which develops the relationship between the correct temperature and the upper and the lower limits of the mercury thermometer. Then we have to put the values that are mentioned in the question in the formula. Once the values are put all we left to do is evaluate and ultimately obtain the required answer.
Complete step by step solution
We know that:
$\dfrac{F-32}{180}=\dfrac{F-L}{U-L}$
Here L is the lower fixed point of the faulty mercury thermometer and U is the upper fixed point of a faulty mercury thermometer.
So now put the values in the formula to get:
$\dfrac{F-32}{180}=\dfrac{F-34}{210-34}$
$\Rightarrow \dfrac{F-32}{180}=\dfrac{F-34}{176}$
$\Rightarrow \dfrac{F-32}{45}=\dfrac{F-34}{44}$
Hence now on we have to further solve the equation, to get:
$45F-45\times 34=44F-44\times 32$
$\Rightarrow 45F-44F=1530-1408$
$\Rightarrow F={{122}^{{}^\circ }}F$
Hence we can say that the correct temperature that is measured by this thermometer is ${{122}^{{}^\circ }}F$.
So the correct option is D.
Note We should all know that the mercury thermometer is defined as a glass tube which is filled with mercury and consists of a temperature scale which is marked on the scale. Whenever there are changes in the temperature the mercury present in the glass tube contracts and expands. The temperature that is obtained after the final contraction and extraction can be read from the scale.
It should be known to us that the upper limit is defined as the largest data value and the lower limit is defined as the smallest data value.
Complete step by step solution
We know that:
$\dfrac{F-32}{180}=\dfrac{F-L}{U-L}$
Here L is the lower fixed point of the faulty mercury thermometer and U is the upper fixed point of a faulty mercury thermometer.
So now put the values in the formula to get:
$\dfrac{F-32}{180}=\dfrac{F-34}{210-34}$
$\Rightarrow \dfrac{F-32}{180}=\dfrac{F-34}{176}$
$\Rightarrow \dfrac{F-32}{45}=\dfrac{F-34}{44}$
Hence now on we have to further solve the equation, to get:
$45F-45\times 34=44F-44\times 32$
$\Rightarrow 45F-44F=1530-1408$
$\Rightarrow F={{122}^{{}^\circ }}F$
Hence we can say that the correct temperature that is measured by this thermometer is ${{122}^{{}^\circ }}F$.
So the correct option is D.
Note We should all know that the mercury thermometer is defined as a glass tube which is filled with mercury and consists of a temperature scale which is marked on the scale. Whenever there are changes in the temperature the mercury present in the glass tube contracts and expands. The temperature that is obtained after the final contraction and extraction can be read from the scale.
It should be known to us that the upper limit is defined as the largest data value and the lower limit is defined as the smallest data value.
Recently Updated Pages
Uniform Acceleration - Definition, Equation, Examples, and FAQs
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Login 2045: Step-by-Step Instructions and Details
Class 11 JEE Main Physics Mock Test 2025
JEE Main Chemistry Question Paper with Answer Keys and Solutions
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Other Pages
NCERT Solutions for Class 11 Physics Chapter 7 Gravitation
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes - CBSE Physics Chapter 1
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
NCERT Solutions for Class 11 Physics Chapter 8 Mechanical Properties of Solids